We will use the formula for the slope:
m = ( y2- y1 ) / ( x2 - x1 )
For PQ : m = ( 0 - 0 ) / ( a + c - 0 ) = 0
For RS : m = ( b - b ) / ( a - ( 2a + c )) = 0
Both slopes are m = 0, so PQ and RS are parallel to x - axis and at the same time parallel to each other ( PQ | | RS ). One pair of opposite sides is parallel.
Answer:
See explanation.
Step-by-step explanation:
2) Your written answer is correct, y = x +4
3) Slope of perpendicular line: 5/2
y=mx+b
4 = (5/2)(4) + b
4 = 10 + b
b = -6
So, y=(5/2)x - 6
4) Slope of perpendicular line: 1
y=mx+b
5 = (1)(4) + b
5 = 4 + b
b = 1
So, y = x + 1
7) Slope of perpendicular line: 3/4
y=mx+b
4 = (3/4)(4) + b
4 = 3 + b
b = 1
So, y = (3/4)x + 1
8) Slope of perpendicular line: 1/4
y=mx+b
-2 = (1/4)(0) + b
b = -2
So, y = (1/4)x - 2
Good. I hope you get locked, most mainly banned. Nobody needs you, “FrIsK”
Answer:
The equation of the graph in slope-intercept form is y = 3x + 7. 2. slope-intercept form is y = x + 2.