<h2>
Hello!</h2>
The answer is:
The lowest term will be:

<h2>Why?</h2>
Reducing a fraction to its lowest term means writing it its simplified form, so, performing the operation and simplifying we have:

Now, to reduce the fraction to its lowest term, we need to divide both numerator and denominator by a common number, for this case, it will be "4" since is the biggest whole number that both numerator and denominator can be divided by, so, we have:

Hence, we have that the lowest term will be:

Have a nice day!
Step-by-step explanation:
Hey there!
The coordinates of a triangle are;
- A (1,2)
- B (1,-2)
- C (-2,-2)
- Scale factor = -4 and centre at (0,0)
Now, We have;
P(x,y)----------- P'(kx, ky)
<u>Keep</u><u> </u><u>formula</u><u>;</u>
<u>A</u><u>(</u><u>1</u><u>,</u><u>2</u><u>)</u><u>----------</u><u> </u><u>A'</u><u>(</u><u>-4</u><u>×</u><u>1</u><u> </u><u>,</u><u>-4</u><u>×</u><u>2</u><u>)</u>
= A'(-4, -8)
B(1,-2)------------- B'(-4,8)
C(-2,-2)-------------C'(8,8)
[ <u>The</u><u> </u><u>A'</u><u> </u><u>should</u><u> </u><u>be</u><u> </u><u>kept</u><u> </u><u>in</u><u> </u><u>(</u><u>-4</u><u>,</u><u>-</u><u>8</u><u>)</u><u>.</u><u> </u><u>There</u><u> </u><u>was</u><u> </u><u>no</u><u> </u><u>place</u><u> </u><u>in</u><u> </u><u>this</u><u> </u><u>graph</u><u> </u><u>so</u><u>,</u><u> </u><u>i</u><u> </u><u>kept</u><u> </u><u>it</u><u> </u><u>just</u><u> </u><u>below</u><u> </u><u>-7</u><u>.</u><u> </u><u>Please</u><u> </u><u>while</u><u> </u><u>plotting</u><u> </u><u>remember</u><u> </u><u>to</u><u> </u><u>keep</u><u> </u><u>it</u><u> </u><u>on</u><u> </u><u>"</u><u>-8"</u><u>.</u><u>]</u>
<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em>
Answer:


Step-by-step explanation:
Let the width of a rectangular garden be 'w'
Length of a rectangular garden = 6 + w
Perimeter of a rectangular garden = 32 feet
<u>
</u><u> </u><u>Finding </u><u>the</u><u> </u><u>width</u><u> </u><u>of</u><u> </u><u>a</u><u> </u><u>rectangular</u><u> </u><u>garden</u> :



Like terms are those which have the same base













Width of a rectangular garden = 5 feet
<u>Substituting </u><u>/</u><u> </u><u>Replacing </u><u>the </u><u>value </u><u>of </u><u>w </u><u>in </u><u>6</u><u> </u><u>+</u><u> </u><u>w </u><u>in </u><u>order </u><u>to </u><u>find</u><u> </u><u>the</u><u> </u><u>length</u><u> </u><u>of</u><u> </u><u>a</u><u> </u><u>rectangular </u><u>garden</u>

<u>Finding</u><u> </u><u>the</u><u> </u><u>area</u><u> </u><u>of</u><u> </u><u>a</u><u> </u><u>rectangular</u><u> </u><u>garden</u><u> </u><u>having</u> <u>length of 11 feet and</u><u> </u><u>width</u><u> </u><u>of</u><u> </u><u>5</u><u> </u><u>feet</u> :



Area of a rectangular garden = 55 ft²
Hope I helped!
Best regards! :D
~
If you can give me more information on this I could help you a bit more respond.
Answer:
y=2
Step-by-step explanation:
<u>note:</u><u> </u><u>it</u><u> </u><u>only</u><u> </u><u>says</u><u> </u><u>to</u><u> </u><u>figure</u><u> </u><u>out</u><u> </u><u>y</u>
x+y+z=4
x+z+y=4
2+y=4 (since x+z=2)
y=4-2
y=2