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Ganezh [65]
3 years ago
13

Please help me with this question.The opposite of 4?

Mathematics
2 answers:
musickatia [10]3 years ago
8 0
The opposite of 4 is -4
lutik1710 [3]3 years ago
8 0
The opposite of 4 is negative 4 :)
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A painting set is shipped in the box shown. The surface area is printed with advertisements.
Shkiper50 [21]

Answer:

528in

Step-by-step explanation:

SA formula: 2Lw + 2Lh + 2hw

for this box: 2(4×10)+2(10×16)+2(4×16)

2(40)+2(160)+2(64)

80+320+128

80+448

<u>528in</u>

3 0
3 years ago
Which of the following is the measure of angle RCP?
enyata [817]

Answer:

From the information provided we have:

PD ≅ RD (= 11)

∠CPD ≅ ∠CRD (= 90°)

They both have CD as the hypotenuse.

=> ΔCPD ≅ ΔCRD

=> ∠PCD ≅ ∠RCD

Now we know that:

∠RCP = ∠PCD + ∠RCD

∠RCP = 2 · ∠RCD

∠RCP = 2 · 33° = 66°

So the answer is B

5 0
3 years ago
Read 2 more answers
Simplify the expression:
Vladimir [108]
The answer Is A. 13p hope it helps
8 0
2 years ago
The square root of a perfect square is not a whole number.
Ipatiy [6.2K]
Hello,

√6.25 =2.5
but √36=6


6 0
3 years ago
NEED ASAP plz. I will also mark brainiest! Don't just take points, I will report you.
PilotLPTM [1.2K]

Part A:

You may choose the two lines connecting the origin and points A and B, and choose the portion of the space between them.

The line between the origin and A is

y = 3x

We want everything below this line (line included), so the first inequality is

y \leq 3x

The line between the origin and B is

y = \dfrac{1}{3}x

We want everything above this line (line included), so the second inequality is

y \geq \dfrac{1}{3}x

Create a system with these two inequalities and you'll have an area including only points A and B

Part B:

To verify the solutions, we can plug the coordinates of A and B in this system and check that we get something true: the coordinates of point A are (1,3), while the coordinates of point B are (3,1). The system becomes:

A:\begin{cases}3 \leq 3\cdot 1\\3 \geq \frac{1}{3}\cdot 1\end{cases},\quad B:\begin{cases}1 \leq 3\cdot 3\\1 \geq \frac{1}{3}\cdot 3\end{cases}

Which means

A:\begin{cases}3 \leq 3\\3 \geq \frac{1}{3}\end{cases},\quad B:\begin{cases}1 \leq 9\\1 \geq 1\end{cases}

And these are all true. So, the system is satisfied, which means that the points belong to the shaded area.

Part C

If you draw the line, you'll see that the only points that lay below the line are B and C. In fact, if we plug the coordinates we have

B:\ 1

And this are both true. You can check the coordinates of all other points, and see that they won't satisfy the inequality y<3x-6

3 0
2 years ago
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