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3 years ago

5

They are all simplest terms

1 answer:

NikAS [45]3 years ago

7 0

Step-by-step explanation:

$- 3(s - 10) + 7( - 2s - 1)$

$- 3s + 30 - 14s - 7$

$- 17s + 23$

is the required answer.

Distributive Property was used here.

Hope it Helps :)

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What is the divisor of 2/7

olga2289 [7]

Answer:

the divisor is 7.

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3 years ago

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On a coordinate plane, kite W X Y Z is shown. Point W is at (negative 3, 3), point X is at (2, 3), point Y is at (4, negative 4)

xz_007 [3.2K]

Answer:

$P = 10 + 2\sqrt{53}$ units

Step-by-step explanation:

Given

Shape: Kite WXYZ

W (-3, 3), X (2, 3),

Y (4, -4), Z (-3, -2)

Required

Determine perimeter of the kite

First, we need to determine lengths of sides WX, XY, YZ and ZW using distance formula;

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}$

For WX:

$(x_1, y_1)\ (x_2,y_2) = (-3, 3),\ (2, 3)$

$WX = \sqrt{(-3 - 2)^2 + (3 - 3)^2}$

$WX = \sqrt{(-5)^2 + (0)^2}$

$WX = \sqrt{25}$

$WX = 5$

For XY:

$(x_1, y_1)\ (x_2,y_2) = (2, 3)\ (4,-4)$

$XY = \sqrt{(2 - 4)^2 + (3 - (-4))^2}$

$XY = \sqrt{-2^2 + (3 +4)^2}$

$XY = \sqrt{-2^2 + 7^2}$

$XY = \sqrt{4 + 49}$

$XY = \sqrt{53}$

For YZ:

$(x_1, y_1)\ (x_2,y_2) = (4,-4)\ (-3, -2)$

$YZ = \sqrt{(4 - (-3))^2 + (-4 - (-2))^2}$

$YZ = \sqrt{(4 +3)^2 + (-4 +2)^2}$

$YZ = \sqrt{7^2 + (-2)^2}$

$YZ = \sqrt{49 + 4}$

$YZ = \sqrt{53}$

For ZW:

$(x_1, y_1)\ (x_2,y_2) = (-3, -2)\ (-3, 3)$

$ZW = \sqrt{(-3 - (-3))^2 + (-2 - 3)^2}$

$ZW = \sqrt{(-3 +3)^2 + (-2 - 3)^2}$

$ZW = \sqrt{0^2 + (-5)^2}$

$ZW = \sqrt{0 + 25}$

$ZW = \sqrt{25}$

$ZW = 5$

The Perimeter (P) is as follows:

$P = WX + XY + YZ + ZW$

$P = 5 + \sqrt{53} + \sqrt{53} + 5$

$P = 5 + 5 + \sqrt{53} + \sqrt{53}$

$P = 10 + 2\sqrt{53}$ units

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3 years ago

In parallelogram abcd what is dc?

MatroZZZ [7]

Dc is a side of the parallelogram

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3 years ago

6.71 x10^8 miles per hour in standard form

xeze [42]

10^8=100000000
100000000x6.71=671,000,000
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3 years ago

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Express the following quantities as ordinary decimal numbers: (step by step please)

jenyasd209 [6]

Answer:

a. 0.0000009 m

b. 6,130, 000, 000

c. 100,000 light years

d. 0.00001 mm

e. 0.0000010 kg

Step-by-step explanation:

Here, we want to come from the standard form to the decimal form

In doing this, we consider the power of 10 attached

If negative, we count leftwards, if positive, we count right-wards

The number of times we count is the power of 10 attached. The count means we are moving the decimal point

For numbers with out visible decimal point, it is at the back of the most right-ward number

Thus, we have these as;

a. 9 * 10^-7

= 0.0000009 m

b. 6.130 * 10^9

= 6,130, 000, 000

c. 1 * 10^5

= 100,000 light years

d. 1 * 10^-5 mm

= 0.00001 mm

e. 10^-7

= 0.0000010 kg

8 0

3 years ago