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8090 [49]
2 years ago
13

Suppose you wish to perform a hypothesis test for a population mean. suppose that the population standard diviation is unknown,

the population is skwed to the right and the sample is large. woudl you perform a z test or a t test
Mathematics
1 answer:
Elenna [48]2 years ago
7 0
You would Perform a z test
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4x when x = 3/4 (I really need help)
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8 0
3 years ago
The heights of women aged 20 to 29 are approximately normal with mean 64 inches and standard deviation 2.7 inches. Men the same
san4es73 [151]

Answer:

Step-by-step explanation:

Z=\frac{x-mu}{\sigma }

X - Heights of women aged 20 to 29: X is N(64, 2.7)

Y - Heights of men aged 20 to 29: X is N(69.3, 2.8)

a) X=6'=72"

Z=\frac{72-64}{2.7} =2.963

b) Y = 72"

z=\frac{72-69.3}{2.8} =0.965

c) 72' women can be taken as very tall but men moderately taller than average

d) Y<5'5" =65"

Z<\frac{65-69.3}{2.8} =-1.536

e) X>73"

Z>\frac{73-64}{2.7} =3.33

Almost 0% can be taken

f) IQR =Q3-Q1

Z scores =

5 0
3 years ago
Can any help me please
PSYCHO15rus [73]
A = 8i + 6j
b = 4i + 5j

ab = (8i + 6j)(4i + 5j)
ab = 8i(4i + 5j) + 6j(4i + 5j)
ab = 8i(4i) + 8i(5j) + 6j(4i) + 6j(5j)
ab = 32i² + 40ij + 24ij + 30j²
ab = 32i² + 64ij + 30j²
ab = <32, 30>

The answer is D.
4 0
2 years ago
What is x^2-28-3x ? ( x^2 means x squares )
Verizon [17]

This is the way to solve the problem

3 0
3 years ago
Read 2 more answers
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