Most of the answers are in the book. 1&2 is based on vocabulary and 8&9 are on the chart
95 + 68,95 = 163,95
6,1% de 163,95 =
(6,1*163,95)/100 =
10,00095 ~ $10,00
The distance covered by the hare and the tortoise in t seconds are 8t and 5t respectively. (Simple Speed-Distance-Time relation)
The tortoise gets a 510m headstart so at t=0 is 1490m.
The functions representing the distance of both of them from the finish line is,
F(x)=2000-8t,. for hare
G(x)=1490-5t,. for tortoise
Answer:
A
Step-by-step explanation:
I am pretty sure this is right and I hope this helps
