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Let present ages of father be x and of son is y years
x/y = 7/2, 2x=7y, y=2x/7
(y+5)=37/100*(x+5)
(2x/7+5)=37/100*(x+5)
(2x+35)/7=(37x+185)/100
200x+3500=259x+1295
259x-250x=3500-1295
59x=2205
x=37.37 years
Answer:
I assume the answer would be that f(x) = 6(x) increases over the interval x = 3 to x = 4
Step-by-step explanation:6 x 3 is 18 and 6 x 4 is 24, so over the interval x = 3 to x = 4 f(x) would increase.
The equation would be x=-2
The answer I believe is 1/t(x^2-3)
I cant type the crippled check mark symbol
