Question

Soo-Jin and mary had an equal number of beads. After soo-jin gave 54 beads to mary. Mary had 7 times as many beads as soo-jin how many beads did they have altogether?

Answer 1

$x\ \ \rightarrow\ \ the\ number\ of\ Soo-Jin's\ beads\\y\ \ \rightarrow\ \ the\ number\ of\ Mary's\ beads\\\\x=y\ \ \ \ \ and\ \ \ \ \ 7\cdot(x-54)=y+54\\\\7x-7\cdot54=x+54\\7x-7\cdot54-x+7\cdot54=x+54-x+7\cdot54\\6x=8\cdot54\ \ /:6\\\\x= \frac{\big{8\cdot54}}{\big{6}} \\\\x= 8\cdot9\\\\x=72\ \ \ \Rightarrow\ \ \ y=72\ \ \ \Rightarrow\ \ \ x+y=2\cdot72=144\\\\Ans.\ \ \ 144\ beads\ altogether$

Answer 2

I cant really get the specific answer but i guess that both of them have 55.96 and then Soo-jin gave 54 to Mary and it left 1.96 so Mary had 109.96 ....1.96(7 times) is exactly 111.120some so ...i think altogether they have is 111.92..that is all i can think for this question.hope it help.