What percent of 200 is 0.5?
1 answer:
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Since we are given no other function, we have to assume that P(x) is the "function from part d".
The average rate of change of P(x) on the interval [60, 80] is given by
rate of change = (P(80) - P(60))/(80 - 60) = (304 -320)/20 = -0.8
The average rate of change of P(x) over [60, 80] is -0.8.
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Units of the rate of change are ($10k)/(1k units) = $10/unit. That is, the profit drops on average $8 per unit on that interval.
The average rate of change of P(x) on the interval [60, 80] is given by
rate of change = (P(80) - P(60))/(80 - 60) = (304 -320)/20 = -0.8
The average rate of change of P(x) over [60, 80] is -0.8.
_____
Units of the rate of change are ($10k)/(1k units) = $10/unit. That is, the profit drops on average $8 per unit on that interval.