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Nikitich [7]
3 years ago
6

Select all the lines below that are an asymptote to the rational function of f(x)= 2x+1/x-9. Picture attached, 15 points and I'l

l give Brainliest! Due in two hours.

Mathematics
1 answer:
dexar [7]3 years ago
5 0

Answer:

<u>Solution : Option A and Option C</u>

Step-by-step explanation:

To determine our vertical asymptote here we can make the denominator of the rational function equivalent to zero ...

x - 9 = 0,

x = 9 - this is our vertical asymptote

Now there are three rules that we need to apply when determining the horizontal asymptote. To do so we take the degree of each " x " term and compare the numerator and denominator degree.

If the numerator (degree) < denominator (degree), we take the degree of the numerator as the asymptote --- (1). If the numerator (degree) = denominator (degree) we take the coefficient of the x terms, and divide --- (2). If the numerator (degree) > denominator (degree) their will be no asymptote.

In this case our degree for the numerator is 1, (x¹) and our degree for the denominator is the same, 1 (x¹). Therefore we divide the coefficients, 2 / 1 = 2. Our horizontal asymptote is y = 2.

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4 years ago
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stellarik [79]
<h3>Answer:  14 feet</h3>

=======================================================

Explanation:

Let C be the corner point.

x = distance from P to C

That makes segment AP to be 70-x feet long

Focus on the right triangle PBC. Use the pythagorean theorem to find the hypotenuse PB.

a^2 + b^2 = c^2\\\\c = \sqrt{a^2 + b^2}\\\\PB = \sqrt{(PC)^2 + (CB)^2}\\\\PB = \sqrt{x^2 + 90^2}\\\\PB = \sqrt{x^2 + 8100}\\\\

If we knew what x was, then we could find a numeric value for PB.

---------------------

It costs $28 per foot to run cable along the ground. This is the portion from A to P. So it costs 28(70-x) dollars to run that portion of cable above ground. Simply multiply the cost per foot by the number of feet.

Similarly, the cost from P to B is 53\sqrt{x^2+8100} since it costs $53 per foot to have it run underground.

The total cost is therefore 28(70-x) + 53\sqrt{x^2 + 8100}

The derivative of this will help determine when the cost is minimized.

Type that function into GeoGebra and have it compute the derivative.

You should find that the x intercept of the derivative curve is exactly x = 56

If x = 56, then 70-x = 70-56 = 14

This means AP = 14 feet is the amount of cable to run along main street.

This also leads to PB = \sqrt{x^2 + 8100} = \sqrt{56^2 + 8100} = 106

The total length of the wire is 14+106 = 120 feet

It costs $28 per foot along the 14 ft section, so 28*14 = 392 dollars is the cost for this section.

It costs $53 per foot along the 106 ft section, so 53*106 = 5618 dollars is the cost for this other section.

The total min cost is 392+5618 = 6010 dollars

------------------

Side note: You could do all this without a calculator to compute the derivative and use algebra to end up with x = 56. However, I think the use of technology is beneficial because it's fast/efficient. In real world settings, you won't be likely to pull out pencil/paper to get things done. The modern world relies on computers. It's refreshing to see that your teacher encourages the use of technology.

Let me know if you need me to go over the algebraic steps and I'll update my answer.

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