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3 years ago

Given f(x) = -x - 2, find x when f(x) = 12.

Mathematics

1 answer:

Flauer [41]3 years ago

3 0

Answer:

We substitute

12 = -x - 2

14 = -x or -x = 14

so the answer is -14!

I am in honors high school algebra and I am 11. Trust me bro.

Step-by-step explanation:

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Round 3184.5641 to the nearest hundred

marysya [2.9K]

You just have to round the hundreds place and leave the rest the same so it is 3200.5641

3 0

3 years ago

Read 2 more answers

Find ∂w/∂s and ∂w/∂t using the appropriate Chain Rule.

Vesnalui [34]

Answer:

<h3>The value of $\frac{\partial w}{\partial s}$ is $e^{3t}-18e^{2s+t}$ </h3><h3>The value of $\frac{\partial w}{\partial t}$ is $3e^{3t}-9e^{2s+t}$ </h3><h3>The partial derivative at s=-5 and t=10 is $\frac{\partial w}{\partial s}$ is $e^{30}-18$ </h3><h3>The partial derivative at s=-5 and t=10 is $\frac{\partial w}{\partial t}=3(e^{30}-3)$ </h3>

Step-by-step explanation:

Given that the Function point are $w=y^3-9x^2y$

$x=e^s$ , $y=e^t$ and s = -5, t = 10

<h3>To find $\frac{\partial w}{\partial s}$ and $\frac{\partial w}{\partial t}$ using the appropriate Chain Rule : </h3>

$w=y^3-9x^2y$

Substitute the values of x and y in the above equation we get

$w=(e^t)^3-9(e^s)^2(e^t)$

$w=e^{3t}-9e^{2s}.e^t$

<h3>Now partially differentiating w with respect to s by using chain rule we have </h3>

$\frac{\partial w}{\partial ∂s}=e^{3t}-9(e^{2s}).2(e^t)$

$=e^{3t}-18e^{2s}.(e^t)$

$=e^{3t}-18e^{2s+t}$

<h3>Therefore the value of $\frac{\partial w}{\partial s}$ is $e^{3t}-18e^{2s+t}$ </h3>

$w=e^{3t}-9e^{2s}.e^t$

<h3>Now partially differentiating w with respect to t by using chain rule we have </h3>

$\frac{\partial w}{\partial t}=e^{3t}.(3)-9e^{2s}(e^t).(1)$

$=3e^{3t}-9e^{2s+t}$

<h3>Therefore the value of $\frac{\partial w}{\partial t}$ is $3e^{3t}-9e^{2s+t}$ </h3>

Now put s-5 and t=10 to evaluate each partial derivative at the given values of s and t :

$\frac{\partial w}{\partial s}=e^{3t}-18e^{2s+t}$

$=e^{3(10}-18e^{2(-5)+10}$

$=e^{30}-18e^{-10+10}$

$=e^{30}-18e^0$

$=e^{30}-18$

<h3>Therefore the partial derivative at s=-5 and t=10 is $\frac{\partial w}{\partial s}$ is $e^{30}-18$ </h3>

$\frac{\partial w}{\partial t}=3e^{3t}-9e^{2s+t}$

$=3e^{3(10)}-9e^{2(-5)+10}$

$=3e^{30}-9e{-10+10}$

$=3e^{30}-9e{0}$

$=3e^{30}-9$

$\frac{\partial w}{\partial t}=3(e^{30}-3)$

<h3>Therefore the partial derivative at s=-5 and t=10 is $\frac{\partial w}{\partial t}=3(e^{30}-3)$ </h3>

6 0

3 years ago

7/10-1/2 in simplest form

Sauron [17]

7/10-1/2=←Write the equation
7/10-5/10=←Make it into a common denominator and subtract
2/10=←Simply if possible
1/5←This is the simplest form

4 0

3 years ago

When we think of surface area - What real-life things do we think of?

zepelin [54]

Answer:

One of my favorite examples is in starting a fire. You can't just hold a match to a log and expect it to work, even though the log and small twigs are the same material and have the same burning point. A cluster of small twigs and splinters bunched up together has a huge surface area compared to a log.

Step-by-step explanation:

7 0

4 years ago

How many 2-digit numbers are multiples of 2 but not 3?

WARRIOR [948]

Answer:

30 numbers

Step-by-step explanation:

Two-digit numbers divisible by 2 are basically just the even two-digit numbers: 10, 12, 14,...96, 98.

Let's collectively divide all these numbers by 2:

10/2 , 12/2 , 14/2 , ... 96/2 , 98/2

5, 6, 7, ... 48, 49

Now subtract 4 from each of them:

5 - 4, 6 - 4, 7 - 4, ... , 48 - 4, 49 - 4

1, 2, 3, ... , 44, 45

So there are 45 multiples of 2 that are two-digit numbers.

The numbers that are both multiples of 2 and 3 are those that are multiples of 6:

12, 18, 24, ... , 96

We want to count how many there are, so divide all these numbers by 6:

12/6 , 18/6 , 24/6 , .... , 96/6

2, 3, 4, .... , 16

There are 15 numbers that are multiples of 2 and 3, so subtract 15 from 45: 45 - 15 = 30

The answer is 30.

Hope this helps!

7 0

4 years ago