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Anna35 [415]
3 years ago
9

Alessialol I will add you back on snap and um I forgot y password to my other acc. so ya and whats the google classroom code?

Mathematics
1 answer:
True [87]3 years ago
5 0

um ok.........................

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Eddi Din [679]
I think the answer is frequency table, but I’m not sure.. make your best guess or try asking other people.
5 0
2 years ago
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Meghan is checking her tax bill for the last year<br> the tax rates were as followed
antoniya [11.8K]
I don’t understand this is there a longer question?
8 0
3 years ago
Which angles are coterminal with an angle drawn in standard position measuring 282°?
vampirchik [111]

Answer:

−438°, -78°, 642°

Step-by-step explanation:

Given angle:

282°

To find the co-terminal angles of the given angle.

Solution:

Co-terminal angles are all those angles having same initial sides as well as terminal sides.

To find the positive co-terminal of an angle between 360°-720° we will add the angle to 360°

So, we have: 282\°+360\°=642\°

To find the negative co-terminal of an angle between 0° to -360° we add it to -360°

So, we have:  282\°-360\°=-78\°

To find the negative co-terminal of an angle between -360° to -720° we add it to -720°

So, we have:   282\°-720\°=-438\°

Thus, the co-terminal angles for  282° are:

−438°, -78°, 642°

7 0
3 years ago
Fins the zeroes of the quadratic equation : 4√ 5 x^ 2 - 24x - 9√ 5
liubo4ka [24]

Answer:

Step-by-step explanation:

Hello,

First of all, we know that the solution of the following equation

   ax^2+bx+c=0

are

   \dfrac{-b\pm\sqrt{b^2-4ac}}{2a} \ \text{ when } \Delta=b^2-4ac \geq 0

<em>I would suggest that you try to apply this formula first and check the solution only after you try.</em>

Let's apply it in this case, we have:

a=4\sqrt{5} \\ \\ b=-24 \\ \\ c= -9\sqrt{5}

\Delta=b^2-4ac=24^2+4*9*5=1296 \\ \\ \sqrt{\Delta}=36 \ \text{ and the solutions are } \\ \\ \\ x_1=\dfrac{24-36}{8\sqrt{5}}=\dfrac{-12}{8\sqrt{5}}=\boxed{\dfrac{-3}{2\sqrt{5}}} \\ \\x_2=\dfrac{24+36}{8\sqrt{5}}=\dfrac{60}{8\sqrt{5}}=\boxed{\dfrac{15}{2\sqrt{5}}}

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

5 0
3 years ago
X^2=3x+3 in standard form​
weeeeeb [17]

Answer:

x^2-3x-3=0

Step-by-step explanation:

x^2=3x+3

x^2-3x-3=0

5 0
3 years ago
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