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3 years ago

How many significant figures are there In the number 10.76

Mathematics

1 answer:

VikaD [51]3 years ago

3 0

Answer:

Number of Significant Figures: 4

The Significant Figures are 1 0 7 6

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Answer this please......

Brrunno [24]

Answer:

1). Option A

2). Option B

Step-by-step explanation:

Question 1

Rule for the dilation of a point by a scale factor 'k' is given by the rule,

(x, y) → (kx, ky)

By this rule image of point A when dilated by the scale factor = 1.25,

A(-12, -8) → A'[(-12 × 1.25), (-8 × 1.25)]

→ A'(-15, -10)

Option A will be the answer.

Question 2

Scale factor = $\frac{\text{Dimension or one side of the image}}{\text{Dimension or one side of the preimage}}$

From the figure attached,

Scale factor = $\frac{F'E'}{FE}$

= $\frac{4}{14}$

= $\frac{2}{7}$

Therefore, rule for the dilation of ABC to form image triangle A'B'C' will be,

(x, y) → $(\frac{2}{7}x, \frac{2}{7}y)$

Option B will be the answer.

8 0

3 years ago

How can you determine if a relation represented as a set of ordered pairs

ddd [48]

Answer:

Hey there!

Using the vertical line test. In a function, one x value only has at most one y value.

Let me know if this helps :)

7 0

3 years ago

The half-life of the isotope Osmium-183 is 12 hours. Choose the equation below that gives the remaining mass of Osmium-183 in gr

raketka [301]

The given equations are incomprehensible, I'm afraid...

You're given that osmium-183 has a half-life of 12 hours, so for some initial mass M₀, the mass after 12 hours is half that:

1/2 M₀ = M₀ exp(12k)

for some decay constant k. Solve for this k :

1/2 = exp(12k)

ln(1/2) = 12k

k = 1/12 ln(1/2) = - ln(2)/12

Now for some starting mass M₀, the mass M remaining after time t is given by

M = M₀ exp(kt )

So if M₀ = 590 g and t = 36 h, plugging these into the equation with the previously determined value of k gives

M = 590 exp(36k) = 73.75

so 73.75 ≈ 74 g of Os-183 are left.

Alternatively, notice that the given time period of 36 hours is simply 3 times the half-life of 12 hours, so 1/2³ = 1/8 of the starting amount of Os-183 is left:

590/8 = 73.75 ≈ 74

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3 years ago

The owner of a book store asked her regular customers to rank 3 items from a list of products that she would like to bring to th

Mrrafil [7]

Bookmarks,pens,stationary

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4 years ago

What are the two numbers with the sum of 1

Yuri [45]

Step-by-step explanation:

0+1 = 1

1/2+1/2= 1

-50 + 51= 1

5 0

3 years ago