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3 years ago

15

What is the answer to this pls answer fast

1 answer:

Bas_tet [7]3 years ago

4 0

Answer:

4/3 = 1.3333

26/3 = 8.6666

Step-by-step explanation:

On a number line, you'd just plot 4/3 a little past 1, and plot 26/3 a little over half past 8.

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Stacey has a square piece of cloth. She cuts 3 inches off of the length of the square and 3 inches

Mamont248 [21]

Answer:

6 in

Step-by-step explanation:

Let x = the side length of the original square.

They removed 3 in from each side of the original square, so the side lengths of the remaining square are x - 3 in.

The area of the smaller square is (x - 3)².

The area of the original square is x²

I assume the area of the smaller square is ¼ that of the original square. Then

1. Solve for x

$\begin{array}{rcl}\frac{1}{4}x^{2} & = & (x - 3)^{2}\\x^{2} & = & 4(x - 3)^{2}\\& = & 4(x^{2} - 6x + 9)\\x^{2}& = & 4x^{2} - 24x + 36\\3x^{2} - 24x + 36 & = & 0\\x^{2} - 8x + 12 & = & 0\\(x - 2)(x - 6) & = & 0\\x - 2 = 0& \qquad &x - 6 = 0\\x = 2& \qquad &x = 6\\\end{array}$

2. Calculate the side length of the smaller square

(a) x = 2

Side length = x - 3 = 2 - 3 = -1 in.

IMPOSSIBLE. You can't have a negative side length.

(b) x = 6

Side length of smaller square = 6 - 3 = 3 in.

Side length of original square = x = 6 in

Check:

$\begin{array}{rcl}\frac{1}{4}(6)^{2} & = & (6 - 3)^{2}\\\frac{1}{4}\times 36 & = & 3^{2}\\9 & = & 9\\\end{array}$

OK.

3 0

3 years ago

Fast pls do this I need it really quick

Tanya [424]

Answer:

1 to 20 to 17 to 29

Step-by-step explanation:

4 0

3 years ago

explain how the relationship between the mean and median provides information about the symmetry or skewness of the data's distr

Klio2033 [76]

Answer:

mean gives you the average of the information, median gives the perfect number. brainliest please

4 0

2 years ago

<img src="https://tex.z-dn.net/?f=%5Cfrac%7B%283a%5E2b%29%5E3%7D%7B9%28ab%29%5E4%7D" id="TexFormula1" title="\frac{(3a^2b)^3}{9(

VladimirAG [237]

You first multiply the outside exponents into the numbers in the parentheses.

When you have an exponent being multiplied directly to another exponent, you multiply the exponents together.

For example(because I am a bad explainer):

$(x^{2} )^4= x^{2(4)} = x^8$

$(x^4)^3 = x^{4(3)} = x^{12}$

When you divide an exponent by an exponent, you subtract the exponents

For example:

$\frac{x^4}{x^1} =x^{4-1}=x^3$

When you have a negative exponent, you move it to the other side of the fraction to make the exponent positive

For example:

$x^{-3}=\frac{1}{x^3}$

$\frac{1}{y^{-5}}=\frac{y^5}{1}=y^5$

$\frac{(3a^2b)^3}{9(ab)^4}$

You can think of it like this if you want:

$\frac{(3^1a^2b^1)^3}{9(a^1b^1)^4}$ Now multiply the outside exponents into the exponents in the parentheses

$\frac{3^3a^6b^3}{9(a^4b^4)} =\frac{27a^6b^3}{9(a^4b^4)}$ Divide 27 and 9

$\frac{3a^6b^3}{a^4b^4} =(3)(a^{6-4})(b^{3-4})=(3)(a^2)(b^{-1})=(3)(a^2)(\frac{1}{b^1})=\frac{3a^2}{b}$

Your answer is $\frac{3a^2}{b}$

5 0

3 years ago

The maximum number of turning points of a 9th degree polynomial is?

Zigmanuir [339]

Answer:

8

Step-by-step explanation:

this was actually in my book and it came in today's test as well but I got 14/20 and failed lol

7 0

2 years ago