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Dmitrij [34]
3 years ago
9

Math Help: Which two answers are correct?

Mathematics
1 answer:
EastWind [94]3 years ago
6 0

Answer:

see below

Step-by-step explanation:

The odd degree (7) tells you the end behaviors are in opposite directions. The negative leading coefficient (-4) tells you the sign of y will be opposite the sign of x.

For x going toward negative infinity, y goes toward positive infinity.

For x going toward positive infinity, y goes toward negative infinity.

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DanielleElmas [232]
Subtract 8 from both sides
So you end up with x = -23
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4 years ago
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How far up does the ladder reach on the building?
pychu [463]

Step-by-step explanation:

The question missing attachment (incomplete)

But the question said how far up does the ladder reach on the building?

See the attachment

Let the tita be 60° and the height of the building be 50 meters

Now

Opposite/hypotenuse = sin(tita)

50/x = sin60°

Cross multiply to find x

x = 50/sin(60°)

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3 years ago
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Find the coordinates of the centroid of triangle RST. SHOW YOUR WORK so I can see if the answer makes sense (no links)
zimovet [89]

Note the coordinates of each point: R(-4, 5), S(5, 1), T(2, -3).

The centroid is the point whose coordinates are the average of the coordinates of R, S, and T.

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<em>y</em>-coordinate: (5 + 1 - 3)/3 = 3/3 = 1

So the centroid is (1, 1).

3 0
3 years ago
Which of the following statements is true? A 15 kg box has more inertia than a 10 kg box. Forces occur in equal and opposite for
Darya [45]
[all of the above] 15kg box moving at same speed as 10kg box obviously has more inertia/energy and ogbects in motion will keep going at same velocity until acted upon by an outside force such as friction or it slamming into stuff and such 

7 0
4 years ago
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Water is drained out of tank, shaped as an inverted right circular cone that has a radius of 4cm and a height of 16cm, at the ra
bearhunter [10]

Answer:

\frac{dh}{dt}=-\frac{1}{2\pi}cm/min

Step-by-step explanation:

From similar triangles, see diagram in attachment

\frac{r}{4}=\frac{h}{16}


We solve for r to obtain,


r=\frac{h}{4}


The formula for calculating the volume of a cone is

V=\frac{1}{3}\pi r^2h


We substitute the value of r=\frac{h}{4} to obtain,


V=\frac{1}{3}\pi (\frac{h}{4})^2h


This implies that,

V=\frac{1}{48}\pi h^3


We now differentiate both sides with respect to t to get,

\frac{dV}{dt}=\frac{\pi}{16}h^2 \frac{dh}{dt}


We were given that water is drained out of the tank at a rate of 2cm^3/min


This implies that \frac{dV}{dt}=-2cm^3/min.


Since we want to determine the rate at which the depth of the water is changing at the instance when the water in the tank is 8cm deep, it means h=8cm.


We substitute this values to obtain,


-2=\frac{\pi}{16}(8)^2 \frac{dh}{dt}


\Rightarrow -2=4\pi \frac{dh}{dt}


\Rightarrow -1=2\pi \frac{dh}{dt}


\frac{dh}{dt}=-\frac{1}{2\pi}






3 0
4 years ago
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