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3 years ago

3x^2/3x^3-18x^2+27x * x^2-9/x

Mathematics

1 answer:

xxMikexx [17]3 years ago

4 0

Answer is in the attachment provided

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A jar holds 128 fluid ounces of juice. The label says the jar has 16 servings. How many fluid ounces are needed for 80 servings?

Bumek [7]

There are 16 servings for each 128 fluid ounces of juice.

Divide 80 servings by 16 servings, and 5 should be the quotient. Therefore, there are 5 jars of juice. Multiply 128 by 5 since 128 fluid ounces are in one jar. The answer should be 640 fluid ounces.

8 0

3 years ago

Read 2 more answers

(4+7 +5+5+2) +[14 5/8+ 14 3/4 +14 7/8+15 + 15 1/8]=

Reptile [31]

Answer:

97 and 1/8

Step-by-step explanation:

(4 + 7 + 5 + 5 + 2) + (14 5/8 + 14 3/4 + 14 7/8 + 15 + 15 1/8)

23 + (14 5/8 + 14 3/4 + 14 7/8 + 15 + 15 1/8)

23 + 74 1/8

97 and 1/8

7 0

2 years ago

Read 2 more answers

Amanda is practicing her dives off the diving board. When she dives into the water, the path her body makes and where she resurf

Vilka [71]

Answer:

The number of feet she will travel back is 1 or 7 feet

Step-by-step explanation:

Here, we need to solve the quadratic equation

That will be as follows;

0 = x^2 -8x + 7

x^2-x-7x+ 7 = 0

x(x-1)-7(x-1) = 0

(x-1)(x-7) = 0

x = 1 or 7

The number of feet she will travel before coming back to the surface of the water is 1 or 7 feet

6 0

2 years ago

Find the six trig function values of the angle 240*Show all work, do not use calculator

-BARSIC- [3]

Solution:

Given:

$240^0$

To get sin 240 degrees:

240 degrees falls in the third quadrant.

In the third quadrant, only tangent is positive. Hence, sin 240 will be negative.

$sin240^0=sin(180+60)$

Using the trigonometric identity;

$sin(x+y)=sinx\text{ }cosy+cosx\text{ }siny$

Hence,

$\begin{gathered} sin(180+60)=sin180cos60+cos180sin60 \\ sin180=0 \\ cos60=\frac{1}{2} \\ cos180=-1 \\ sin60=\frac{\sqrt{3}}{2} \\ \\ Thus, \\ sin180cos60+cos180sin60=0(\frac{1}{2})+(-1)(\frac{\sqrt{3}}{2}) \\ sin180cos60+cos180sin60=0-\frac{\sqrt{3}}{2} \\ sin180cos60+cos180sin60=-\frac{\sqrt{3}}{2} \\ \\ Hence, \\ sin240^0=-\frac{\sqrt{3}}{2} \end{gathered}$

To get cos 240 degrees:

240 degrees falls in the third quadrant.

In the third quadrant, only tangent is positive. Hence, cos 240 will be negative.

$cos240^0=cos(180+60)$

Using the trigonometric identity;

$cos(x+y)=cosx\text{ }cosy-sinx\text{ }siny$

Hence,

$\begin{gathered} cos(180+60)=cos180cos60-sin180sin60 \\ sin180=0 \\ cos60=\frac{1}{2} \\ cos180=-1 \\ sin60=\frac{\sqrt{3}}{2} \\ \\ Thus, \\ cos180cos60-sin180sin60=-1(\frac{1}{2})-0(\frac{\sqrt{3}}{2}) \\ cos180cos60-sin180sin60=-\frac{1}{2}-0 \\ cos180cos60-sin180sin60=-\frac{1}{2} \\ \\ Hence, \\ cos240^0=-\frac{1}{2} \end{gathered}$

To get tan 240 degrees:

240 degrees falls in the third quadrant.

In the third quadrant, only tangent is positive. Hence, tan 240 will be positive.

$tan240^0=tan(180+60)$

Using the trigonometric identity;

$tan(180+x)=tan\text{ }x$

Hence,

$\begin{gathered} tan(180+60)=tan60 \\ tan60=\sqrt{3} \\ \\ Hence, \\ tan240^0=\sqrt{3} \end{gathered}$

To get cosec 240 degrees:

$\begin{gathered} cosec\text{ }x=\frac{1}{sinx} \\ csc240=\frac{1}{sin240} \\ sin240=-\frac{\sqrt{3}}{2} \\ \\ Hence, \\ csc240=\frac{1}{\frac{-\sqrt{3}}{2}} \\ csc240=-\frac{2}{\sqrt{3}} \\ \\ Rationalizing\text{ the denominator;} \\ csc240=-\frac{2}{\sqrt{3}}\times\frac{\sqrt{3}}{\sqrt{3}} \\ \\ Thus, \\ csc240^0=-\frac{2\sqrt{3}}{3} \end{gathered}$

To get sec 240 degrees:

$\begin{gathered} sec\text{ }x=\frac{1}{cosx} \\ sec240=\frac{1}{cos240} \\ cos240=-\frac{1}{2} \\ \\ Hence, \\ sec240=\frac{1}{\frac{-1}{2}} \\ sec240=-2 \\ \\ Thus, \\ sec240^0=-2 \end{gathered}$

To get cot 240 degrees:

$\begin{gathered} cot\text{ }x=\frac{1}{tan\text{ }x} \\ cot240=\frac{1}{tan240} \\ tan240=\sqrt{3} \\ \\ Hence, \\ cot240=\frac{1}{\sqrt{3}} \\ \\ Rationalizing\text{ the denominator;} \\ cot240=\frac{1}{\sqrt{3}}\times\frac{\sqrt{3}}{\sqrt{3}} \\ \\ Thus, \\ cot240^0=\frac{\sqrt{3}}{3} \end{gathered}$

5 0

10 months ago

What is the volume of the planter that measures 60l, 60w. 60h?

andre [41]

The volume of the planter that measures 60 l, 60 w. 60 h (D) 216000 cm³

<u>Explanation:</u>

Length, l = 60 cm

Width, w = 60 cm

Height, h = 60 cm

Volume, v = ?

We know,

Volume = length ×width × height

Substitute the values in the formula.

$v = 60 X 60 X 60\\\\v = 216,000 cm^3$

Therefore, the volume of the planter is 216,000 cm³

8 0

3 years ago