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dalvyx [7]
3 years ago
15

HELP PLEASE

Mathematics
2 answers:
anyanavicka [17]3 years ago
5 0

Answer:   9\sqrt{2}

Step-by-step explanation:

The given expression: \sqrt{8}+3\sqrt{2}+\sqrt{32}

We know that

\sqrt{8}=\sqrt{2\times2\times2}\\\\=\sqrt{2^2\times2}\\\\=2\sqrt{2}

\sqrt{32}\\\\=\sqrt{2\times2\times2\times2\times2}\\\\=\sqrt{4^2\times2}\\\\=4\sqrt{2}

Now, substitute the value of \sqrt{8} and \sqrt{32} in the given expression , we get

2\sqrt{2}+3\sqrt{2}+4\sqrt{2}\\\\=9\sqrt{2}

valentinak56 [21]3 years ago
3 0
\sqrt{8}+3\sqrt{2}+\sqrt{32}\\\\\sqrt{4*2}+3\sqrt{2}+\sqrt{16*2}\\\\2\sqrt{2}+3\sqrt{2}+4\sqrt{2}\\\\9\sqrt{2}

Your answer is the third option.
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