Question

HELP PLEASE

Answer 1

Answer:   $9\sqrt{2}$

Step-by-step explanation:

The given expression: $\sqrt{8}+3\sqrt{2}+\sqrt{32}$

We know that

$\sqrt{8}=\sqrt{2\times2\times2}\\\\=\sqrt{2^2\times2}\\\\=2\sqrt{2}$

$\sqrt{32}\\\\=\sqrt{2\times2\times2\times2\times2}\\\\=\sqrt{4^2\times2}\\\\=4\sqrt{2}$

Now, substitute the value of $\sqrt{8}$ and $\sqrt{32}$ in the given expression , we get

$2\sqrt{2}+3\sqrt{2}+4\sqrt{2}\\\\=9\sqrt{2}$

Answer 2

$\sqrt{8}+3\sqrt{2}+\sqrt{32}\\\\\sqrt{4*2}+3\sqrt{2}+\sqrt{16*2}\\\\2\sqrt{2}+3\sqrt{2}+4\sqrt{2}\\\\9\sqrt{2}$

Your answer is the third option.