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3 years ago

Please Help ! Will Reward Brainliest , Thank You In Advanced.

Mathematics

1 answer:

chubhunter [2.5K]3 years ago

4 0

The answer is y ≤ 8
put dot/closed circle on 8 then draw an arrow to the left all the way till 3 or pass 3 ←-----------------

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On a coordinate plane, 4 lines are shown. Line L M goes through (negative 5, negative 3) and (0, 3). Line N O goes through (nega

miv72 [106K]

Answer:

The slope of line LM is perpendicular to the given line.

Step-by-step explanation:

L (- 5, - 3), M (0, 3)

N (- 6, - 5) , O (0, 0)

J (- 6, 1) , K (0, - 4)

Slope of given line = -5/6

Slope of perpendicular line = 6/5

Slope of line LM

$\frac{3 + 3}{0 + 5}=\frac{6}{5}$

Slope of line NO

$\frac{0+5}{0+6}=\frac{5}{6}$

Slope of line JK

$\frac{-4-1}{0+6}=\frac{-5}{6}$

4 0

3 years ago

Exhibit a population of ten integers having mean=20 and variance=4

Alla [95]

exhibit population for ten integers is 15,19,19,20,20,20,21,22,22,22 mean is 20 variance is 4

Step-by-step explanation:

Mean is helps in finding the mid point of the data.
Variance is the variability of data it was here.
In order to get the data straight the combination of 4 was required.
4 is variance one data set was 19 other had to be 22.
As mean is 20 three means had to be 20.
from mean 20 4 is greater then 20 and 3 is less then 20.
15 being the lowest it compensated the variance to 4.
Mathematically there are many ways to do this using function.
This is to be found out at a traditional method.
Reducing or increase the number as it was integers.

8 0

3 years ago

Find x pleaseee!!! Will give branliest

den301095 [7]

Answer:

This is an isosceles triangle.

So, we have:

Tangent 32 = x/11

Tangent 32 (11) = x

x = 6.874

Let me know if this helps!

8 0

3 years ago

23. Drug Testing Job Applicants Find the probability of selecting someone who uses drugs.

Dovator [93]

Answer:

Step-by-step explanation:

7 0

3 years ago

The two points (-2,4) and (4,2) are the endpoints of the diameter of a circle. What is the equation of this circle in standard f

stepladder [879]

$Center\ of\ the\ circle\ is\ the\ midpoint\ AB\ where\ A(-2;\ 4)\ \&\ B(4;\ 2)\\\\center:O\left(\frac{-2+4}{2};\ \frac{4+2}{2}\right)\to O(1;\ 3)\\\\Radius\ of\ the\ circle\ is\ distance\ O\ to\ A:\\\\r=|OA|=\sqrt{(-2-1)^2+(4-3)^2}=\sqrt{9+1}=\sqrt{10}\\\\Equation\ of\ a\ circle:\\\\(x-a)^2+(y-b)^2=r^2\ whete\ center\ is\ (a;\ b)\ and\ radius\ is\ r.\\\\Equation\ of\ this\ circle:\\\\(x-1)^2+(y-3)^2=(\sqrt{10})^2\\\\(x-1)^2+(y-3)^2=10$

3 0

4 years ago