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otez555 [7]
3 years ago
13

In the Venn diagram, consider U = {whole numbers 1-100}

Mathematics
2 answers:
Dmitry [639]3 years ago
6 0
The question is what numbers satisfy A ∩ C.

The symbol ∩ means intersection, .i.e. you need to find the numbers that belong to both sets A and C. Those numbers might belong to the set C or not, because that is not a restriction.

Then lets find the numbers that belong to both sets, A and C.

Set A: perfect squares from A to 100:

1^2 = 1
2^2 = 4
3^2 = 9
4^2 = 16
5^2 = 25
6^2 = 36
7^2 = 49
8^2 = 64
9^2 = 81
10^2 = 100

=> A = {1, 4, 9, 16, 25, 36, 49, 64, 81, 100}

Set C: perfect fourths

1^4 = 1
2^4 = 16
3^4 = 81

C = {1, 16, 81?

As you see, all the perfect fourths are perfect squares, so the intersection of A and C is completed included in A. this is:

A ∩ C = C or A ∩ C = 1, 16, 81

On the other hand, the perfect cubes are:

1^3 = 1
2^3 = 8
3^3 = 27
4^3 = 81

B = {1, 8, 27, 81}

That means that the numbers 1 and 81 belong to the three sets, A, B, and C.

In the drawing you must place the number 16 inside the region that represents the intersection of A and C only, and the numbers 1 and 81 inside the intersection of the three sets A, B and C.
Maksim231197 [3]3 years ago
6 0

Answer:

1, 16, 81

Step-by-step explanation:

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aivan3 [116]

Answer:

Step-by-step explanation:

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3 years ago
The points A, B, and C lie on a line so that AB = 12 cm and BC = 13.5 cm. Find the length of segment AC. Give all possible answe
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Answer:

25.5 and 1.5

Step-by-step explanation:

AC = 12 cm

BC = 13.5 cm

12 + 13.5 = 25.5 cm

13.5 - 12 = 1.5 cm

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2 years ago
Please help me with this
Nikitich [7]

Answer: Your answer is A,C, and D

Step-by-step explanation:

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2 years ago
Which of the following statements about check-cashing companies is FALSE?
Alexeev081 [22]

Answer:

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6 0
2 years ago
MATH HELP!!! 100PTS!!!
Lostsunrise [7]

Answer:

x =\dfrac{20 +\sqrt{454}}{18}, \quad \dfrac{20 -\sqrt{454}}{18}

Step-by-step explanation:

<u>Given functions</u>:

  p(x)=2x-4

  r(x)=\dfrac{6x-1}{9x+1}

Solve for p(x) = r(x):

\begin{aligned}p(x) & = r(x)\\\implies 2x-4 & = \dfrac{6x-1}{9x+1}\\(2x-4)(9x+1)&=6x-1\\18x^2+2x-36x-4&=6x-1\\18x^2-40x-3&=0\end{aligned}

As the found quadratic equation cannot be factored, use the Quadratic Formula to solve for x:

<u>Quadratic Formula</u>

x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0

Therefore:

a=18, \quad b=-40, \quad c=-3

Substitute the values of a, b and c into the <u>quadratic formula</u> and solve for x:

\begin{aligned}\implies x & =\dfrac{-(-40) \pm \sqrt{(-40)^2-4(18)(-3)} }{2(18)}\\\\& =\dfrac{40 \pm \sqrt{1816}}{36}\\\\& =\dfrac{40 \pm \sqrt{4 \cdot 454}}{36}\\\\& =\dfrac{40 \pm \sqrt{4}\sqrt{454}}{36}\\\\& =\dfrac{40 \pm2\sqrt{454}}{36}\\\\& =\dfrac{20 \pm\sqrt{454}}{18}\end{aligned}

Therefore, the solutions are:

x =\dfrac{20 +\sqrt{454}}{18}, \quad \dfrac{20 -\sqrt{454}}{18}

Learn more about quadratic equations here:

brainly.com/question/27750885

brainly.com/question/27739892

6 0
1 year ago
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