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amid [387]
3 years ago
7

Use the common multiple of 24

Mathematics
1 answer:
max2010maxim [7]3 years ago
8 0

Answer:

24, 48, 72, 96, 120

Step-by-step explanation:

I can keep going on but i learned to just put at least 5 and if the person needs  more then just give them ten more

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How much food would you get if you had 40 bannanas and 30 apples but you lost 20 of the 30 apples?
Juli2301 [7.4K]

Answer: You would have 40 bananas and 10 apples or 50 pieces of fruit

Step-by-step explanation:

30-20=10

3 0
3 years ago
‼️‼️‼️‼️‼️‼️<br> PLEASE HELP <br> FIRST ANSWER GETS BRAINLIEST <br> NO LINK NO LINKS OR BANNED
vodka [1.7K]

Answer:

The true statements are (D) and (E). This is a square with sides equal to 5 units so that means that its perimeter is 4×(5 units) or 20 units and its area is (5 units)×(5 units) or 25 units^2.

5 0
3 years ago
List at least five importance of having self discipline m following protocol during enhanced community quarantine in your respec
Maksim231197 [3]

Answer:

no clue -0- if I knew I would tell you

4 0
2 years ago
A professor wishes to discover if seniors skip more classes than freshmen. Suppose he knows that freshmen skip 2% of their class
KIM [24]

Answer:

We conclude that seniors skip more than 2% of their classes at 0.01 level of significance.

Step-by-step explanation:

We are given that a professor wishes to discover if seniors skip more classes than freshmen. Suppose he knows that freshmen skip 2% of their classes.

He randomly samples a group of seniors and out of 2521 classes, the group skipped 77.

<u><em /></u>

<u><em>Let p = percentage of seniors who skip their classes.</em></u>

So, Null Hypothesis, H_0 : p \leq 2%   {means that seniors skip less than or equal to 2% of their classes}

Alternate Hypothesis, H_A : p > 2%   {means that seniors skip more than 2% of their classes}

The test statistics that will be used here is <u>One-sample z proportion</u> <u>statistics</u>;

                                   T.S.  = \frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }  ~ N(0,1)

where, \hat p = sample proportion of seniors who skipped their classes = \frac{77}{2521}

           n = sample of classes = 2521

So, <u><em>test statistics</em></u>  =  \frac{\frac{77}{2521} -0.02}{{\sqrt{\frac{\frac{77}{2521}(1-\frac{77}{2521})}{2521} } } } }

                               =  3.08

The value of the test statistics is 3.08.

Now at 0.01 significance level, <u>the z table gives critical value of 2.3263 for right-tailed test</u>. Since our test statistics is more than the critical value of z as 2.3263 < 3.08, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis</u>.

Therefore, we conclude that seniors skip more than 2% of their classes.

6 0
3 years ago
2/7 = /56 find the sum simply when need
Ludmilka [50]

Answer:

The answer is 2/7 = 16/56

8 0
3 years ago
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