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4 years ago

7

Pls help me with this

1 answer:

saul85 [17]4 years ago

7 0

Answer:

The coordinates of S is ( 4 , -20 )

Step-by-step explanation:

To solve this you figure out how ( 0 , 4 ) relates to ( 2 , -8 ).

You can see that the 0 was added by 2, and the 4 was subtracted by 12 to make ( 2 , -8 ).

Now that you see how they relate, you can find the next point by repeating this pattern.

2 + 2 = 4

-8 - 12 = -20

( 4 , -20 )

I hope this helped! :)

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The unbalanced wheel has a mass of 15 kg and rolls without slipping on the flat horizontal surface. The wheel has a radius of gy

miv72 [106K]

Answer:

a) $a_w=4.331m/s^2$

b) $F=53.7N$

c) $\mu=96.5N$

Step-by-step explanation:

From the question we are told that

mass of unbalanced wheel $M=15kg$

Radius of gyration $G=64m$

Mass center $M_c =40mm=$ $4*10^{-2} m$

Angular velocity $\omega=4rads/s$

a)

Generally the equation for moment at point A is mathematically given as

$\sum M_a=I \alpha+\sum M \=ad$

Where $a_w=wheel\ accelaration$

$15*9.81*(0.04)=0.06144*\frac{a_w}{0.1}+15(0.04)(0.04)\frac{a_w}{0.1}+(15a_w-15(0.04)(4^2)0.1)$

$5,87=(a_w*0.8544+15a_0-0.96)$

$a_w=4.331m/s^2$

b)

Generally the equation for equilibrium of system on the horizontal axis is mathematically given as

$\sum f_x=ma_w$

$F=ma_w-m \=r w^2$

$F=(25*4.221)-(15*0.04*4^2)$

$F=63.3-9.6$

$F=53.7N$

c)

Generally the equation for equilibrium of system on the vertical axis is mathematically given as

$\sum f_y=ma_w$

Where

$F=\mu-mg+m \=r \alpha$

$\alpha=\frac{a_0}{0.1}$

$\mu-mg+m \=r \alpha=0$

$\mu-15*9.81+15*0.04*\frac{4.221}{0.1}$

$\mu-96.5N=0$

$\mu=96.5$

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