A thumb-wrestling match requires two thumbs, so we can either suppose that we need at least two people

, or allow one to thumb-wrestle one's self. In either case, we'd have

, so let's just say we need a minimum of two players.
If we add one more person to the set of players, then the first two people would need to play 1 additional match each. So

.
If we add one more person, then the first three people would again each have to play 1 more match with the new person. So

.
And so on, so that in general, the number of games needed for everyone to play exactly one match with everyone else is given recursively by
15/66 I think you might be able to simplify
Answer:
Today is Monday, May 17, 2021
Answer:
88 divided by 8 is 11.
Step-by-step explanation:
You can't use the distributive property for this problem because there is no distributing to be done, but the answer is 11.