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iragen [17]
3 years ago
7

-6(2)divided by (-3)

Mathematics
2 answers:
Akimi4 [234]3 years ago
3 0

Answer:

4

Step-by-step explanation:

Following PEMDAS order:

-6*2=-12

-12/-3=4

inessss [21]3 years ago
3 0

Answer:

-6(2)(-3)

-3+2

-5

Step-by-step explanation:

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Solve for the variable x<br><br> m = -12g + x
mario62 [17]

Answer:

x=m+12g

Step-by-step explanation:

m=-12g+x

making x subject of formula, we have,

x=m+12g

3 0
3 years ago
An area is approximated to be 14 in 2 using a left-endpoint rectangle approximation method. A right- endpoint approximation of t
USPshnik [31]
The trapezoidal approximation will be the average of the left- and right-endpoint approximations.

Let's consider a simple example of estimating the value of a general definite integral,

\displaystyle\int_a^bf(x)\,\mathrm dx

Split up the interval [a,b] into n equal subintervals,

[x_0,x_1]\cup[x_1,x_2]\cup\cdots\cup[x_{n-2},x_{n-1}]\cup[x_{n-1},x_n]

where a=x_0 and b=x_n. Each subinterval has measure (width) \dfrac{a-b}n.

Now denote the left- and right-endpoint approximations by L and R, respectively. The left-endpoint approximation consists of rectangles whose heights are determined by the left-endpoints of each subinterval. These are \{x_0,x_1,\cdots,x_{n-1}\}. Meanwhile, the right-endpoint approximation involves rectangles with heights determined by the right endpoints, \{x_1,x_2,\cdots,x_n\}.

So, you have

L=\dfrac{b-a}n\left(f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1})\right)
R=\dfrac{b-a}n\left(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n)\right)

Now let T denote the trapezoidal approximation. The area of each trapezoidal subdivision is given by the product of each subinterval's width and the average of the heights given by the endpoints of each subinterval. That is,

T=\dfrac{b-a}n\left(\dfrac{f(x_0)+f(x_1)}2+\dfrac{f(x_1)+f(x_2)}2+\cdots+\dfrac{f(x_{n-2})+f(x_{n-1})}2+\dfrac{f(x_{n-1})+f(x_n)}2\right)

Factoring out \dfrac12 and regrouping the terms, you have

T=\dfrac{b-a}{2n}\left((f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1}))+(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n))\right)

which is equivalent to

T=\dfrac12\left(L+R)

and is the average of L and R.

So the trapezoidal approximation for your problem should be \dfrac{14+21}2=\dfrac{35}2=17.5\text{ in}^2
4 0
3 years ago
Can you guys help me with all 3 questions please would really appreciate it.
Temka [501]

Answer:

Number 1 is 17 cents

Number 2 is 164.35

Number 3 is 213

Step-by-step explanation:

Please mark brainliest

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3 years ago
Distance between points (1,2) (4,3)
GREYUIT [131]

Answer:

3.1

Step-by-step explanation:

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If you can, please help me! I'll give brainliest (if I can.)​
dlinn [17]

Answer:

The intersection of the sets A, B, and C is Bird.

Set B contains Fish, Lizard, Turtle, Bird, and Dog.

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