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max2010maxim [7]
3 years ago
10

What is the difference between multiplying monomials and adding/subtracting monomials?

Mathematics
1 answer:
mario62 [17]3 years ago
5 0

EX. 3x+3x. You will leave the variable alone. You add the constants (3 and 3). The answer is 6. Because of that x, the answer is 6x.

EX. 3x times 3x. Again you will leave the x alone. You multiply the constants (3 and 3). The answer is 9. Because of the x, the answer is 9x.

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10 Adoya deposited sh 4000 for 2 years in a bank which paid 122% p.a. simple interest. What interest did he get after two years?
olga nikolaevna [1]

Answer:

9760

Step-by-step explanation:

Interest=((P.A.)*(Interest Rate)*(Time))/100

Interest=(4000*122*2)/100

Interest=9760

5 0
3 years ago
Read 2 more answers
Solve the linear system using multiplication Elimination.<br><br> 4х + Зу = 8<br> X - 2y = 13
motikmotik
X=5, y=-4
(5,-4)
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5 0
3 years ago
NUMBER 27 please!!!!!!!
Artist 52 [7]
The inequality can be:
150x \leqslant 3000
Now you divide both sides by 150 to get the #of boxes.

3000 \div 150
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3 0
3 years ago
Which exponential function is represented by the
Leno4ka [110]

Answer:

C, f(x) = 3(2)^x

Step-by-step explanation:

Since the y-intercept is 3, the function will have 3 multiplying by some number to the power of x.

As x increases by 1, we notice that y multiplies by 2 every time.

This leads us to believe that the equation is 3 * 2^x

8 0
3 years ago
Factor completely x^8- 16.
Nataly_w [17]

Answer:

Step-by-step explanation:


So in this example we'll be using the difference of squares which essentially states that: (a-b)(a+b)=a^2-b^2 or another way to think of it would be: a-b=(\sqrt{a}-\sqrt{b})(\sqrt{a}+\sqrt{b}). So in this example you'll notice both terms are perfect squares. in fact x^n is a perfect square as long as n is even. This is because if it's even it can be split into two groups evenly for example, in this case we have x^8. so the square root is x^4 because you can split this up into (x * x * x * x) * (x * x * x * x) = x^8. Two groups with equal value multiplying to get x^8, that's what the square root is. So using these we can rewrite the equation as:

x^8-16 = (x^4-4)(x^4+4)

Now in this case you'll notice the degree is still even (it's 4) and the 4 is also a perfect square, and it's a difference of squares in one of the factors, so it can further be rewritten:

x^4-4 = (x^2-2)(x^2+2)

So completely factored form is: (x^2-2)(x^2+4)(x^4+4)

I'm assuming that's considered completely factored but you can technically factor it further. While the identity difference of squares technically only applies to difference of squares, it can also be used on the sum of squares, but you need to use imaginary numbers. Because x^2+4 = x^2-(-4). and in this case a=x^2 and b=-4. So rewriting it as the difference of squares becomes: x^4+4 = x^4 - (-4) = (x^2-\sqrt{-4})(x^2+\sqrt{-4}) = (x^2-2i)(x^2+2i) just something that might be useful in some cases.

7 0
2 years ago
Read 2 more answers
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