Answer:
A
Explanation:
the answer is a glucose hope this helps
<span>b. more like other protists than members of other kingdoms.</span>
Answer:
D. The methyl group of acetyl CoA becomes radio-labeled
Explanation:
During the steps in glycolysis, the carbon at position 1, becomes C-1 in dihydroxyacetone phosphate during the cleavage of fructose-1,6-bisphosphate to dihydroxyacetone phosphate and glyceraldehyde-3-phosphate. Subsequently on isomerization of dihydroxyacetone phosphate to glyceraldehyde-3-phosphate, C-1 of dihydroxyacetone phosphate becomes C-3 of glyceraldehyde-3-phosphate.
Furthermore, in pyruvate, the end product of glycolysis, C-3 is converted to a methyl group which then becomes the methyl group in the acetyl-CoA molecule produced from the oxidative decarboxylation of pyruvate.
Since the radioactive 14-C of radio-labeled glucose occupies position 1, it will become the methyl group of acetyl-CoA.
Answer:
The correct answer is C.
Explanation:
An unidentified material that consists of cells must be from a
living organism.
It sounds more like an theory.
Its "prophase" because "nuclear envelope fragments and the microtubules have to attach to the chromosomes", so in short its the longest stage because everything is <span>decondensing, splitting apart, and the nucleus is disintegrating, also chromosomes are getting ready to be duped. </span>
