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hodyreva [135]
3 years ago
9

Answers to 5 and 6 please need help please!

Mathematics
1 answer:
Tresset [83]3 years ago
8 0

My friend says 5 is 60 and 6 is b.

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Needddddd helpppppp asapppp/ Necesitoooo ayudaaaaa rapidooo
belka [17]

Answer:

42 cm^2

Step-by-step explanation:

armyphobic

6 0
3 years ago
Given <br><img src="https://tex.z-dn.net/?f=%20log_%7B2%7D%28x%29%20%20%3D%20%20%5Cfrac%7B3%7D%7B%20log_%7Bxy%7D%282%29%20%7D%20
Naily [24]

Answer:

\displaystyle y = x^{-\frac{2}{3}}

Step-by-step explanation:

<u>Logarithms</u>

Some properties of logarithms will be useful to solve this problem:

1. \log(pq)=\log p+\log q

2. \displaystyle \log_pq=\frac{1}{\log_qp}

3. \displaystyle \log p^q=q\log p

We are given the equation:

\displaystyle \log_{2}(x) = \frac{3}{ \log_{xy}(2) }

Applying the second property:

\displaystyle  \log_{xy}(2)=\frac{1}{ \log_{2}(xy)}

Substituting:

\displaystyle \log_{2}(x) = 3\log_{2}(xy)

Applying the first property:

\displaystyle \log_{2}(x) = 3(\log_{2}(x)+\log_{2}(y))

Operating:

\displaystyle \log_{2}(x) = 3\log_{2}(x)+3\log_{2}(y)

Rearranging:

\displaystyle \log_{2}(x) - 3\log_{2}(x)=3\log_{2}(y)

Simplifying:

\displaystyle -2\log_{2}(x) =3\log_{2}(y)

Dividing by 3:

\displaystyle \log_{2}(y)=\frac{-2\log_{2}(x)}{3}

Applying the third property:

\displaystyle \log_{2}(y)=\log_{2}\left(x^{-\frac{2}{3}}\right)

Applying inverse logs:

\boxed{y = x^{-\frac{2}{3}}}

7 0
3 years ago
11/28+4/7 = simplest form
MatroZZZ [7]
The answer to this question is 27/28
4 0
3 years ago
Find the area of the figure<br> A) 450MM<br> B) 67,500 MM<br> C) 600MM<br> D)150MM
Sphinxa [80]
Thats it option (C). Hope it helps!!

5 0
3 years ago
Read 2 more answers
Fill in the table using this function rule.<br> y = 6x + 5
ddd [48]

Answer:

x=3, y=23

x=6, y=41

x=8, y=53

x=9, y=59

Step-by-step explanation:

x=3, y=6(3)+5

        y=18+5

        y= 23

x=6, y=6(6)+5

       y=36+5

       y= 41

x=8, y=6(8)+5

       y=48+5

       y=53

x=9, y=6(9)+5

       y=54+5

       y=59

8 0
3 years ago
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