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rjkz [21]
3 years ago
12

Apply the zero matirx: [16 -24] + [ 0 0 ]=[ x y] X=? Y=?

Mathematics
1 answer:
Ainat [17]3 years ago
5 0

Answer:

x = 16

y = -24

Step-by-step explanation:

Recall that the addition of matrices is done when matrices are of the same dimension. In this case, you are in fact adding matrices of the same dimension (dimension 1x2). Recall as well that in the addition of matrices, the elements of each matrix combine only with the element located in the exact same position in the other matrix.

So for this case the first element of the first matrix "16" combines with the first element of the second matrix "0" resulting in an element of value16 + 0 =16 in the new matrix.

Equally, the second element of the first matrix "-24" combines with the second element of the second matrix, resulting in : -24 + 0 = -24.

Therefore, the matrix resultant from this addition is: [16   -24] (same form of the first matrix, which indicates that adding a zero matrix to an existing matrix will not change the first matrix.

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Maksim231197 [3]
-12 + 3x + 2 = 5x - 10 - 8x 
-10 + 3x = -3x -10
-10 + 6x = -10
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3 years ago
Please help FAST I need the answer along with you explaining the steps so I can get it thanks! I’ll give Brainlist also!
kupik [55]

Answer:

The equation of required line is: \mathbf{5x-8y+34=0}

Step-by-step explanation:

We need to write equation in the form Ax+By+C=0 of the line parallel to 5x-8y+12=0 and through the point (-2,3)

First we need to find slope and y-intercept of the required line.

Using equation of line  5x-8y+12=0 to find slope.

Since the given line and required lines are parallel there slope is same.

Writing equation in slope intercept form: y=mx+b where m is slope.

5x-8y+12=0 \\-8y=-5x-12\\\frac{-8y}{-8y}=\frac{-5x}{-8}-\frac{12}{-8}\\y=\frac{5}{8}x+\frac{3}{4}

So, the slope m = 5/8

The slope of required line is m=\frac{5}{8}

Now finding y-intercept using slope m=\frac{5}{8} and point(-2,3)

y=mx+b\\3=\frac{5}{8}(-2)+b\\3=\frac{-5}{4}+b\\b=3+\frac{5}{4}\\b=\frac{3*4+5}{4}\\b=\frac{12+5}{4}\\b=\frac{17}{4}

So, the equation of required line having slope m=\frac{5}{8}  and y-intercept b=\frac{17}{4}

y=mx+b\\y=\frac{5}{8}x+\frac{17}{4}\\y=\frac{5x+17*2}{8}\\y= \frac{5x+34}{8}  \\8y=5x+34\\5x-8y+34=0

So, The equation of required line is: \mathbf{5x-8y+34=0}

3 0
3 years ago
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