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Paladinen [302]
3 years ago
14

Which number, when placed in the box, will make the equation true?

Mathematics
1 answer:
taurus [48]3 years ago
8 0

\mathsf{\heartsuit\;\; (\sqrt{8})^2 = \sqrt{64}}\\\\\mathsf{\heartsuit\;\; [(8)^\frac{1}{2}]^2 = \sqrt{(8)^2}}\\\\\mathsf{\heartsuit\;\; (8)^\frac{2}{2} = [(8)^2]^\frac{1}{2}}\\\\\mathsf{\heartsuit\;\; 8 = [8]^\frac{2}{2}}\\\\\mathsf{\heartsuit\;\; 8 = 8}\\\\\mathsf{\heartsuit\;\; Option\;(A)\;is\;the\;Answer}

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Please help! I'll give points and make you brainliest ​
jasenka [17]

Answer:

1/81

Step-by-step explanation:

5 0
3 years ago
An angle's supplement is nine times of its complementary angle. Find the measure of the angle, the complement of the angle,and t
Masja [62]

Answer:

Measure of required angle = 78.75° , measure of  complementary angle  = 11.25° and measure of supplementary angle = 101.25°

Step-by-step explanation:

let assume measure of required angle = x

since sum of angle and its supplement is 180°

so x + supplement of x = 180

⇒ supplement of x  = 180 - x

since sum of angle and its complement is 90

so x + complement of x = 90

⇒ complement of x = 90 - x

Form given information

supplement of x = 9 × ( complement of x)

⇒180 - x = 9 × ( 90 - x )

⇒ 180 - x = 810 - 9x

⇒ -x + 9x = 810 - 180

⇒ 8x = 630

⇒ x = 630/8 = 78.75°

complement of x = 90 - x = 90 - 78.75° = 11.25°

and supplement of x = 180 - 78.75  = 101 .25°

we can recheck our solution by multiplying complement by 9 , that is 11.25 × 9 = 101.25 which is same as supplement. Hence our solution is correct.

So we can conclude that measure of required angle = 78.75° , measure of  complementary angle  = 11.25° and measure of supplementary angle = 101.25°


8 0
3 years ago
This season, Lisa's lacrosse team has won 2/3 of their home games (games played at Lisa's school), but just 2/5 of their away ga
denis23 [38]
The team has played 24 home games.
Let h be the number of home games and a be the number of away games.  The total number of games is 49; this gives ush+a=49
They won 2/3 of the home games and 2/5 of the away games; there were 26 games won.  This gives us2/3h + 2/5a = 26
In the first equation we isolate h by subtracting a from both sides:h+a-a=49-ah=49-a
Substitute this into the second equation:2/3(49-a)+2/5a = 26
Using the distributive property, we have2/3*49 - 2/3*a + 2/5a = 2698/3 - 2/3a + 2/5a = 26
Finding a common denominator to combine like terms, we have98/3 - 10/15a + 6/15a = 2698/3 - 4/15a = 26
We want to convert the whole number to thirds as well; 26 = 26*3/3 = 78/3:98/3 - 4/15a = 78/3
Subtracting 98/3 from both sides:98/3 - 4/15a - 98/3 = 78/3 - 98/3-4/15a = -20/3
Divide both sides by -4/15:a = -20/3 ÷ -4/15a = -20/3 × - 15/4 = 300/12 = 25
There were 25 away games.
This means there were 49-25 = 24 home games.
5 0
3 years ago
The window shown is the shape of a semicircle with a radius of 6 feet. The distance from F to E is 3 feet and the measure of = 4
Brut [27]
We have to find 2 areas and to subtract A2 from A1:
A1 = ( r² · π · 45° ) / 360° = ( 6² · 3.14 · 45° ) / 360° = 14.13 ft²
A2 = ( 3² · π · 45° ) / 360° = 3.53 ft²
A ( BCIH ) = 14.13 - 3.53 = 10.6 ft² ≈ 11 ft²
Answer: The area of the glass in the region BCIH is 11 ft² ( rounded to the nearest square foot ).
5 0
4 years ago
Read 2 more answers
What are the solutions to the equation? x^2+6x = 40.
GaryK [48]

Answer:

x = 4, -10

Step-by-step explanation:

Find the zeros of the equations.

Solve the equation:

x^2 + 6x = 40

Subtract -40 from both sides.

x^2 + 6x - 40 = 0

Factor the equation.

(x - 4)(x + 10)

Solve for x with the given information by equaling it to 0.

x - 4 = 0

Add 4 to both sides

x = 4

x + 10 = 0

Subtract 10 from both sides

x = -10

This means that our x values are:

x = 4, -10

6 0
3 years ago
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