(opposite angles in a parallelogram)
(subtraction)
(angles in a triangle add to 180 degrees)
(adjacent angles in a parallelogram are supplementary)
(subtraction)
(angles in a triangle add to 180 degrees)
(angles on a straight line add to 180 degrees)
Answer:
O C. 5.76 in2
Step-by-step explanation:
To find the <u>area</u> of a square, the formula is
length x width = area
length = 2.4
width = 2.4
2.4in x 2.4in = 5.76 in2
in2 is the part of the answer since in x in = in2
Some basic formulas involving triangles
\ a^2 = b^2 + c^2 - 2bc \textrm{ cos } \alphaa 2 =b 2+2 + c 2
−2bc cos α
\ b^2 = a^2 + c^2 - 2ac \textrm{ cos } \betab 2=
m_b^2 = \frac{1}{4}( 2a^2 + 2c^2 - b^2 )m b2 = 41(2a 2 + 2c 2-b 2)
b
Bisector formulas
\ \frac{a}{b} = \frac{m}{n} ba =nm
\ l^2 = ab - mnl 2=ab-mm
A = \frac{1}{2}a\cdot b = \frac{1}{2}c\cdot hA=
\ A = \sqrt{p(p - a)(p - b)(p - c)}A=
p(p−a)(p−b)(p−c)
\iits whatever A = prA=pr with r we denote the radius of the triangle inscribed circle
\ A = \frac{abc}{4R}A=
4R
abc
- R is the radius of the prescribed circle
\ A = \sqrt{p(p - a)(p - b)(p - c)}A=
p(p−a)(p−b)(p−c)
Answer:
18.85
Step-by-step explanation:
2(3.14)(3)
No, Vijay cannot fit all cubes into the box.
Solution:
Total number of cubes = 50
Volume of each cube = 1 cubic inch
Number of cubes fit in the bottom of the box = 12
Area of the box<em> = l</em> × <em>b</em> = 12 square inch
Height of the box = 4 inch
Volume of the box = <em> l</em> × <em>b </em>× h
= 12 × 4
Volume of the box = 48 cubic inch
So, 48 cubes can only fit in the box.
Hence, Vijay cannot fit 50 cubes into the box.
