in a distribution where the mean is to the right of the median, the histogram of the distribution will probably
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Because these are all congruent, and they're all vertical angles, this would show you that what ever you would do to one side, you do also to the other side.
(56+41)= (97).
Then we do, 180-97= (83).
![\left[\begin{array}{ccc}\boxed{\bfx=83}}\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Cboxed%7B%5Cbfx%3D83%7D%7D%5Cend%7Barray%7D%5Cright%5D%20)
(56+41)= (97).
Then we do, 180-97= (83).