All categories

3 years ago

My son hasn't knows how to do that can somebody help him please .

Mathematics

1 answer:

kobusy [5.1K]3 years ago

3 0

A ratio compares two quantities.

How may days are in May? <span>31
How many days in a year? </span>365

Now, we are being asked to compare may to a year.

Answer: 31 to 365

Now, the other is easy also.

A triangle has 3 sides, and a square has 4.

Answer: 3 to 4

Find equal ratio's

8/12 = 2/3 = 4/6 = 16/24

20/25 = 4/5 = 40/50 = 80/100

Done! Enjoy! :) I hope I helped your son. Take care.

You might be interested in

If a polynomial function f(x) has roots 3 and sq root 5 and -6, what must be a factor of f(x)

Nana76 [90]

Step-by-step explanation:

$\text{If}\ a,\ b\ \text{and}\ c\ \text{are the zeros of a polynomial, then we can write this}\\\text{polynomial in form:}\\\\p(x)=(x-a)(x-b)(x-c)\bigg(r(x)\bigg)\\\\\text{where}\ \ r(x)\ \text{is other polynomial or number}.\\\\\text{Therefore}\\\\\text{if a polynomial function}\ f(x)\ \text{has roots (zeros):}\ 3,\ \sqrt5\ \text{and}\ -6,\\\text{then we can write it in form:}\\\\f(x)=(x-3)(x-\sqrt5)(x-(-6)\bigg(r(x)\bigg)\\\\f(x)=(x-3)(x-\sqrt5)(x+6)\bigg(r(x)\bigg)$

$\text{The factors of this polynomial function are:}\\\\x-3,\ x-\sqrt5\ \text{and}\ x+6.$

4 0

3 years ago

The number of knots in a particular type of wood has a Poisson distribution with an average of 1.6 knots in 10 cubic feet of the

HACTEHA [7]

Answer:

0.994 = 99.4% probability that a 10-cubic-foot block of the wood has at most 5 knots.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

1.6 knots in 10 cubic feet of the wood.

This means that $\mu = 1.6$

Find the probability that a 10-cubic-foot block of the wood has at most 5 knots.

$P(X \leq 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-1.6}*(1.6)^{0}}{(0)!} = 0.202$

$P(X = 1) = \frac{e^{-1.6}*(1.6)^{1}}{(1)!} = 0.323$

$P(X = 2) = \frac{e^{-1.6}*(1.6)^{2}}{(2)!} = 0.258$

$P(X = 3) = \frac{e^{-1.6}*(1.6)^{3}}{(3)!} = 0.138$

$P(X = 4) = \frac{e^{-1.6}*(1.6)^{4}}{(4)!} = 0.055$

$P(X = 5) = \frac{e^{-1.6}*(1.6)^{5}}{(5)!} = 0.018$

$P(X \leq 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0.202 + 0.323 + 0.258 + 0.138 + 0.055 + 0.018 = 0.994$

0.994 = 99.4% probability that a 10-cubic-foot block of the wood has at most 5 knots.

5 0

3 years ago

A student needs to make a square cardboard piece. The cardboard should have a perimeter equal to at least 92 inches. The functio

Illusion [34]

Answer:

$s\geq 23$

Step-by-step explanation:

We are given that a student needs to make a square cardboard piece.

Perimeter of cardboard should be equal to atleast 92 inches

We have to find that which shows reasonable domain for f(s)

Let s be the side of square cardboard

We know that perimeter of square =f(s=) $4\times side$

Then, perimeter of cardboard= $4s$

$4s\geq 92$

Dividing by 4 on both sides

$s\geq 23$

Hence, the domain of function $[23,\infty)$

Therefore, option d is true.

Answer:d: $s\geq 23$

6 0

4 years ago

Let the random variable x be equally likely to assume any of the values 1/10, 1/5, or 3/10. determine the mean and variance of x

Keith_Richards [23]

Since the values are equally likely and equally spaced, their mean is the middle one.
the mean is 1/5

The variance is the average of the square of the deviations from the mean.
σ² = (1/3)((-1/10)² + 0² + (1/10)²) = 2/300
the variance is 2/300

6 0

3 years ago

Find the area of the part of the paraboloid z = 9 - x^2 - y^2 that lies above the xy-plane.

svetoff [14.1K]

Parameterize this surface (call it $S$ ) by