Take the derivative:
g’(x) = 12x^3 - 24x^2
Set equal to zero and solve:
0 = 12x^3 - 24x^2
0 = 12x^2 (x - 2)
x = 0 or x = 2
Plug back into original
g(0) = 3(0^4) - 8(0^3)
g(0) = 0 - 0
g(0) = 0
g(2) = 3(2^2) - 8(2^3)
g(2) = 3(4) - 8(8)
g(2) = 12 - 64
g(2) = -52
There is an absolute max at (0,0) or when x = 0
Answer: About 12.083
Explanation:
In order to solve this you would use Pythagorean theorem.
You are given the length of the two legs (5 and 11)
So by plugging in 5 and 11 into A Squared plus B Squared = C Squared, you get that C^2= 146.
By finding the square root of both sides you get square root of 146, which is approximately 12.803
Answer:
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Step-by-step explanation:
Answer:
Step-by-step explanation:
Answer is C: x-min = 0, x-max= 30, y-min = 0, y-max = 30
Answer:
16 sqrt(30)
Step-by-step explanation:
2√20 × 4√6
Multiply
2*4 sqrt(20*6)
8 sqrt(120)
Simplifying
8 sqrt(4 *30)
We know sqrt(ab) = sqrt(a) sqrt(b)
8 sqrt(4) sqrt(30)
8 *2* sqrt(30)
16 sqrt(30)