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3 years ago

What Is the value of c-1=8

Mathematics

2 answers:

harina [27]3 years ago

6 0

This is the equation:

c - 1 = 8
c = 8 + 1
c = 9

Hope it helped,

Happy homework/ study/ exam!

algol [13]3 years ago

5 0

C-1=8
c=8+1
c=9.........

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How you find 8 and 10

Fittoniya [83]

Answer:

8. X = 10.5 and 19. X = 5

Step-by-step explanation:

8. You know that a triangle interior angles should add up to 180° so:

(10x - 11) + (3x - 2) + (3x + 1) = 180

180 = 16x - 12

168 = 16x

The you divide each side by 16:

168 ÷ 16 = 16x ÷ 16

X = 10.5

10. You know that a straight line equals 180° and interior angles add up to 180° so:

1st you do 180 - 151 = 29°

2nd (11x - 1) + (20x - 3) + (29) = 180

180 = 31x + 25

155 = 31x

The you divide each side by 31:

155 ÷ 31 = 31x ÷ 31

X = 5

8 0

3 years ago

An acute angle θ is in a right triangle with sin θ = six sevenths. What is the value of cot θ?

inysia [295]

$\sin \theta =\dfrac{6}{7}\\
\cot \theta=\dfrac{x}{6}\\
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x^2=49-36\\
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x=\sqrt{13}\\
\boxed{\cot \theta =\dfrac{\sqrt{13}}{6}}$

4 0

3 years ago

Read 2 more answers

ANSWER FAST PLZ 20POINTS!!!!!!!!!!!!!!!!!!

Marianna [84]

Answer: 272 square feet

Step-by-step explanation:

We must find the total area of the backyard then subtract the area of the not allowed area from it. Clearly, the length and width of the backyard is 22 and 17ft respectively, so the total area is 22*17=374ft^2.

The restricted space can be seen as two rectangles, both with width 3 and length 17, making their area 2(17*3) =102

374-102= 272

6 0

4 years ago

Find the value of given expression<br><br>=》<br><img src="https://tex.z-dn.net/?f=32%20%2B%2032%20%20%5Cdiv%2032" id="TexFormula

adell [148]

Answer:

The answer will be 33

Step-by-step explanation:

No explanation

4 0

4 years ago

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A firm has the marginal-demand function Upper D prime (x )equalsStartFraction negative 1200 x Over StartRoot 25 minus x squared

vovangra [49]

Answer:

The demand function is $\mathbf{D(x) = 1200(\sqrt{25-x^2})+ 124000}$

Step-by-step explanation:

A firm has the marginal-demand function $D' x = \dfrac{-1200}{\sqrt{25-x^2 } }$ .

Find the demand function given that D = 16,000 when x = $4 per unit.

What we are required to do is to find the demand function D(x);

If we integrate D'(x) with respect to x ; we have :

$\int\limits \ D'(x) \, dx = \int\limits{\dfrac{-1200 x}{\sqrt{25-x^2}} } \, dx$

$D(x) = \int\limits{\dfrac{-1200 x}{\sqrt{25-x^2}} } \, dx$

Let represent t with $\sqrt{25-x^2}}$

The differential of t with respect to x is :

$\dfrac{dt}{dx}= \dfrac{1}{2 \sqrt{25-x^2}}}(-2x)$

$\dfrac{dt}{dx}= \dfrac{-x}{ \sqrt{25-x^2}}}$

${dt}= \dfrac{-xdx}{ \sqrt{25-x^2}}}$

replacing the value of $\dfrac{-xdx}{ \sqrt{25-x^2}}}$ for dt in $D(x) = \int\limits{\dfrac{-1200 x}{\sqrt{25-x^2}} } \, dx$

So; we can say :

$D(x) = \int\limits{\dfrac{-1200 x}{\sqrt{25-x^2}} } \, dx$

$D(x) = 1200\int\limits{\dfrac{- x}{\sqrt{25-x^2}} } \, dx$

$D(x) = 1200\int\limits \ dt$

$D(x) = 1200t+ C$

Let's Recall that :

t = $\sqrt{25-x^2}}$

Now;

$\mathbf{D(x) = 1200(\sqrt{25-x^2}})+ C}$

GIven that:

D = 16,000 when x = $4 per unit.

i.e

D(4) = 16000

SO;

$D(x) = 1200(\sqrt{25-x^2}})+ C$

$D(4) = 1200(\sqrt{25-4^2}})+ C$

$D(4) = 1200(\sqrt{25-16}})+ C$

$D(4) = 1200(\sqrt{9}})+ C$

$D(4) = 1200(3}})+ C$

16000 = 1200 (3) + C

16000 = 3600 + C

16000 - 3600 = C

C = 12400

replacing the value of C = 12400 into $\mathbf{D(x) = 1200(\sqrt{25-x^2}})+ C}$ , we have:

$\mathbf{D(x) = 1200(\sqrt{25-x^2})+ 124000}$

∴ The demand function is $\mathbf{D(x) = 1200(\sqrt{25-x^2})+ 124000}$

5 0

3 years ago