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Sedaia [141]
3 years ago
14

What Is the value of c-1=8

Mathematics
2 answers:
harina [27]3 years ago
6 0
This is the equation:

c - 1 = 8
c = 8 + 1 
c = 9


Hope it helped,

Happy homework/ study/ exam!
algol [13]3 years ago
5 0
C-1=8
c=8+1
c=9.........
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Adam is training a group of cyclists. Each cyclist completes a 10-kilometer time trial during training. Adam records the times,
nydimaria [60]

The histogram which shows the results of the time trial is option B

<h3>Histogram</h3>

Given data:

12:32, 12:46, 13:30, 15:03, 13:43, 13:46, 14:20, 14:29, 12:34, 14:43, 15:26, 16:02, 16:16, 14:38, 16:55, 17:10, 14:26, 17:21, 17:58, 13:30

Grouping of data,:

12:00 - 12:59 = 3

13:00 - 13:59 = 4

14:00 - 14:59 = 5

15:00 - 15:59 = 2

16:00 - 16:59 = 3

17:00 - 17:59 = 3

  • The frequency is represented on the y-axis(number of cyclist)
  • The time is represented on the x-axis

Learn more about histogram:

brainly.com/question/9388601

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7 0
2 years ago
Find the difference between 7/10 and 1/5
mrs_skeptik [129]

Answer:

Its d 5/10

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
T5 ( volume of cylinder )
yan [13]

Answer:

Step-by-step explanation:

V=\pi r^2h=\pi *20^2*8 ≈ 10053.1in^3

4 0
3 years ago
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The volume of a right circular cone with radius r and height h is V = pir^2h/3.
Scorpion4ik [409]

The question is incomplete. The complete question is :

The volume of a right circular cone with radius r and height h is V = pir^2h/3. a. Approximate the change in the volume of the cone when the radius changes from r = 5.9 to r = 6.8 and the height changes from h = 4.00 to h = 3.96.

b. Approximate the change in the volume of the cone when the radius changes from r = 6.47 to r = 6.45 and the height changes from h = 10.0 to h = 9.92.

a. The approximate change in volume is dV = _______. (Type an integer or decimal rounded to two decimal places as needed.)

b. The approximate change in volume is dV = ___________ (Type an integer or decimal rounded to two decimal places as needed.)

Solution :

Given :

The volume of the right circular cone with a radius r and height h is

$V=\frac{1}{3} \pi r^2 h$

$dV = d\left(\frac{1}{3} \pi r^2 h\right)$

$dV = \frac{1}{3} \pi h \times d(r^2)+\frac{1}{3} \pi r^2 dh$

$dV = \frac{2}{3} \pi r h (dr)+\frac{1}{3} \pi r^2 dh$

a). The radius is changed from r = 5.9 to r = 6.8 and the height is changed from h = 4 to h = 3.96

So, r = 5.9  and dr = 6.8 - 5.9 = 0.9

     h = 4  and dh = 3.96 - 4 = -0.04

Now, $dV = \frac{2}{3} \pi r h (dr)+\frac{1}{3} \pi r^2 dh$

$dV = \frac{2}{3} \pi (5.9)(4)(0.9)+\frac{1}{3} \pi (5.9)^2 (-0.04)$

$dV=44.484951 - 1.458117$

$dV=43.03$

Therefore, the approximate change in volume is dV = 43.03 cubic units.

b).  The radius is changed from r = 6.47 to r = 6.45 and the height is changed from h = 10 to h = 9.92

So, r = 6.47  and dr = 6.45 - 6.47 = -0.02

     h = 10  and dh = 9.92 - 10 = -0.08

Now, $dV = \frac{2}{3} \pi r h (dr)+\frac{1}{3} \pi r^2 dh$

$dV = \frac{2}{3} \pi (6.47)(10)(-0.02)+\frac{1}{3} \pi (6.47)^2 (-0.08)$

$dV=-2.710147-3.506930$

$dV= -6.22$

Hence, the approximate change in volume is dV = -6.22 cubic units

8 0
3 years ago
-8y^10 / 2y^5<br> write using positive exponents
Rashid [163]

Answer:

Step-by-step explanation:

\dfrac{a^{m}}{a^{n}}=a^{m-n}\\\\\dfrac{-8y^{10}}{2y^{5}}=\dfrac{-4y^{10}}{y^{5}}=-4*y^{10-5}= -4y^{5}

3 0
3 years ago
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