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3 years ago

Which expressions are equivalent to j+j+2k

Mathematics

2 answers:

Paha777 [63]3 years ago

7 0

I can’t see the photo but if you combine the like terms, you will get 2j + 2k.

Hope this helps!

butalik [34]3 years ago

3 0

Answer:

$2j+2k$

Step-by-step explanation:

You didn't give any options so:

j+j+2k=

<em>Combine like terms</em>

2j+2k

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at a party at the middle school over on third avenue next to the bank, $60\%$ of the students are seventh graders. these student

Vaselesa [24]

There are 600 students including the seventh and eighth graders at the party.

This problem uses the concept of percentages to define the conditions that are laid in front of us.

Let the original number of students be S , and the number of seventh graders be = 0.60S

We know that percent is used to convey the mathematical term of a fraction multiplied by 100.

Total students after 20 eighth graders arrive = S + 20

And we have that

Number of seventh graders / total number of students = 58%

.60S / [ S + 20 ] = .58 we multiply both sides by S + 20

0.60S =0 .58 [ S + 20]

.60S = .58S + 11.6 we subtract 0.58S from both the sides

0.02S = 11.6 we divide both the sides by .02

S = 11/6 / 0.02 = 580

So the total number of students = 580 + 20 = 600 .

Hence there are 600 students at the party at that time.

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1 year ago

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8090 [49]

Answer

5 and 90

Step-by-step explanation:

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3 years ago

Read 2 more answers

At what value of x does the graph of the following function F(x) have a

Free_Kalibri [48]

Answer:

Step-by-step explanation:

Given

f(x) = $\frac{1}{x+2}$

The denominator cannot be zero as this would make f(x) undefined.

Equating the denominator to zero and solving gives the value that x cannot be and if the numerator is non zero for this value then it is a vertical asymptote.

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3 years ago

Prove that: 5^31–5^29 is divisible by 100.

ANEK [815]

Answer:

See explanation

Step-by-step explanation:

Consider the expression

$5^{31}-5^{29}$

First, factor it:

$5^{31}-5^{29}=5^{29}\cdot(5^2-1)=5^{29}\cdot (25-1)=24\cdot 5^{29}$

Note that

$100=25\cdot 4$

Then

$5^{31}-5^{29}=24\cdot 5^{29}=6\cdot 4\cdot 25\cdot 5^{27}=6\cdot 100\cdot 5^{27}$

This shows that number 100 is a factor of the expression $5^{31}-5^{29}$ and, therefore, this expression is divisible by 100.

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3 years ago

How would i anser this select all the ratios equivalent to 4:6

Natali5045456 [20]

If we try to simplify the ratio or try to multiply both by any number, we will get the equivalent ratio

Like :

$\frac{4}{6} \\$

Divide ( simplify ) by 2

$\frac{ \frac{4}{2} }{ \frac{6}{2} } \\ \\ \\ = > \frac{2}{3}$

Or multiply by any number,

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2 years ago