Which expressions are equivalent to j+j+2k

Mathematics

2 answers:

Paha777 [63]4 years ago

7 0

I can’t see the photo but if you combine the like terms, you will get 2j + 2k.

Hope this helps!

butalik [34]4 years ago

3 0

Answer:

$2j+2k$

Step-by-step explanation:

You didn't give any options so:

j+j+2k=

Combine like terms

2j+2k

You might be interested in

If a figure is a trapezoid in what other way can you classify It?

scoray [572]

It is also a quadrilateral

3 0

4 years ago

Read 2 more answers

ΔWXY, the measure of ∠Y=90°, WY = 8, YX = 15, and XW = 17. What ratio represents the tangent of ∠X?

valina [46]

The ratio Tangent is the opposite side over the adjacent side of the angle.
Tan (x) = 8/15

8 0

3 years ago

Chad casts a shadow that is 14.3 feet long. The straight-line distance from the top of Chad’s head to the end of the shadow crea

Elan Coil [88]

Imagine right triangle with first leg to be the Chad length and second leg to be the Chad's shadow. Second leg has length 14.3 ft and since the straight-line distance from the top of Chad’s head to the end of the shadow creates a 23° angle with the ground, you could consider the trigonmetric function

$\tan 23^{\circ}= \dfrac{\text{Chad's length}}{\text{Chad's shadow length}}$ ,

then $\tan 23^{\circ}= \dfrac{\text{Chad's length}}{14.3}, \\ \text{Chad's length}=14.3\cdot \tan 23^{\circ}=6.1$ .

4 0

3 years ago

Please help me with this problem

My name is Ann [436]

Answer:

$6A- 8B = \left[\begin{array}{ccc}56&50&-14\\-126&92&62\\-78&26&2\end{array}\right]$

Option A is correct.

Step-by-step explanation:

$A=\left[\begin{array}{ccc}-4&-1&-9\\-9&6&9\\-1&-1&3\end{array}\right] \\B=\left[\begin{array}{ccc}-10&-7&-5\\9&-7&-1\\9&-4&2\end{array}\right]$

We need to find 6A - 8B

Multiply matrix A with 6 and matrix B with 8 and then subtract 6A - 8B

$6A=\left[\begin{array}{ccc}-24&-6&-54\\-54&36&54\\-6&-6&18\end{array}\right] \\8B=\left[\begin{array}{ccc}-80&-56&-40\\72&-56&-8\\72&-32&16\end{array}\right]\\6A - 8B =\left[\begin{array}{ccc}-24-(-80)&-6-(-56)&-54-(-40)\\-54-(72)&36-(-56)&54-(-8)\\-6-(72)&-6-(-32)&18-(16)\end{array}\right] \\6A - 8B =\left[\begin{array}{ccc}-24+80&-6+56&-54+40\\-54-72&36+56&54+8\\-6-72&-6+32&18-16\end{array}\right] \\6A- 8B = \left[\begin{array}{ccc}56&50&-14\\-126&92&62\\-78&26&2\end{array}\right]$