A.....................,,;;;;:::::.....,,,...,,,..,,.,,,,,
Set up a proportion:
1/7 L of water - 1/9 of the aquarium
x L of water - 1 aquarium (the whole aquarium)
![\frac{\frac{1}{7}}{\frac{1}{9}}=\frac{x}{1} \\ \\ \frac{1}{7} \times 9=x \\ \\ \frac{9}{7}=x \\ \\ x=1 \frac{2}{7}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cfrac%7B1%7D%7B7%7D%7D%7B%5Cfrac%7B1%7D%7B9%7D%7D%3D%5Cfrac%7Bx%7D%7B1%7D%20%5C%5C%20%5C%5C%0A%5Cfrac%7B1%7D%7B7%7D%20%5Ctimes%209%3Dx%20%5C%5C%20%5C%5C%0A%5Cfrac%7B9%7D%7B7%7D%3Dx%20%5C%5C%20%5C%5C%0Ax%3D1%20%5Cfrac%7B2%7D%7B7%7D)
1 2/7 liters of water are needed to fill the aquarium.
<h2>$
19,254.32</h2>
Step-by-step explanation:
Let
be the tuition fee last year.
% of last year's tuition fee is ![\frac{5.1x}{100}](https://tex.z-dn.net/?f=%5Cfrac%7B5.1x%7D%7B100%7D)
It is given that the tuition fee increased by
%
It is given that ![x=18320](https://tex.z-dn.net/?f=x%3D18320)
So,![\text{new fee}=x+\frac{5.1x}{100}](https://tex.z-dn.net/?f=%5Ctext%7Bnew%20fee%7D%3Dx%2B%5Cfrac%7B5.1x%7D%7B100%7D)
![\text{new fee}=18320+\frac{5.1\times 18320}{100}=18320+934.32=19254.32](https://tex.z-dn.net/?f=%5Ctext%7Bnew%20fee%7D%3D18320%2B%5Cfrac%7B5.1%5Ctimes%2018320%7D%7B100%7D%3D18320%2B934.32%3D19254.32)
So,the tuition fee for this year is $19254.32