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WINSTONCH [101]

3 years ago

11

a football team scored 529 points one season and then 376 points the next. About how many points less did the team score in the

second season? Round to the nearest ten.

1 answer:

tamaranim1 [39]3 years ago

5 0

150 is your answer :

You might be interested in

Another one these :(

erma4kov [3.2K]

Answer:

Obtuse and Isosceles

Step-by-step explanation:

Since there is an angle greater than 90 degrees (104 degrees) the triangle is obtuse. Since there are two congruent sides, the triangle is also Isosceles.

7 0

3 years ago

A car salesperson sells a used car for $ and earns % of the sale price as commission. How many dollars does the salesperson ea

Arisa [49]

You haven't provided the $ or % that he gets, but I will attempt to use algebraic terms to explain it instead.

If the salesman sells a car for $<em>a</em> and gets <em>b</em>% of the sale price as commission, then what you need to do is divide the <em>a</em> by 100, then multiply it by <em>b</em> to find out <em>b</em>% of <em>a</em>. This will be the commission that he will earn.

<em>a </em>/ 100 x <em>b</em> = commission earned in $

Edit

<em>You've now supplied me with the $ and %, let me explain it again.</em>

To find out the commission that he will earn, you divide 8,100 by 100 then multiply it by 9.

8,100 / 100 = 81

81 x 9 = $729 commission earned.

8 0

3 years ago

Read 2 more answers

The data for Shawn's phone has 32000 megabytes if storage for photos . She wants to increase the amount by 4% if each photo uses

Law Incorporation [45]

Answer:

Yes, she will have have enough new memory for 200 additional photos.

Step-by-step explanation:

Given:

Initial memory for storage, $M_{o}=32000\textrm{ megabytes}$

Increase in memory $=4%$

Therefore, increase in memory, $\Delta M=\frac{4}{100}\times 32000=1280\textrm{ megabytes}$

Now, memory consumed by 1 photo = 5 megabytes

So, memory consumed by 200 additional photos = $200\times 5=1000\textrm{ megabytes}$

Memory left in her phone = 1280 - 1000 = 280 megabytes

Therefore, she will have additional 280 megabytes of memory left in her phone.

As memory consumed by 200 additional photos is less than that of the increase in memory, therefore, she does have enough new memory for 200 additional photos.

6 0

3 years ago

Use the data set to determine which statements are correct. Check all that apply. 115, 120, 118, 104, 109, 148, 135, 141, 139 Th

Karo-lina-s [1.5K]

Question

Use the data set to determine which statements are correct. Check all that apply. 115, 120, 118, 104, 109, 148, 135, 141, 139

a)The median is 120.

b)The median is 109.

c)There is an outlier.

d) The lower quartile is 118.

e)The lower quartile is 112.

f)The upper quartile is 140.

g)The upper quartile is 141.

h))The interquartile range is 28.

Answer:

a)The median is 120.

e)The lower quartile is 112

f)The upper quartile is 140

h)The interquartile range is 28

Step-by-step explanation:

We are given the above Data sets:

115, 120, 118, 104, 109, 148, 135, 141, 139

To confirm the correct options, we have to find the median, lower and upper quartile and the interquartile range

115, 120, 118, 104, 109, 148, 135, 141, 139

We have to find rearrange this numbers from lowest to highest

Hence we have:

104, 109, 115, 118, 120, 135, 139, 141, 148

1) Median

104, 109, 115, 118, 120, 135, 139, 141, 148

The formula for median =

1/2(n + 1)th value

n = number of terms = 9

=1/2(9 + 1)th value

= 1/2(10)th value

= 5th value

The median is the 5th value = 120

Option a) is correct

2) Lower Quartile

The formula for lower quartile=

1/4(n + 1)th value

n = 9

= 1/4(9 + 1)th value

= 1/4(10)th value

= 2.5th value

This means the value is between the 2nd and 3rd values

109= 2nd value

115= 3rd value

First Quartile = 109+ 115/2

= 224/2

= 112

Therefore, Option e)The lower quartile is 112.

3)Upper Quartile

The formula for upper quartile=

3/4(n + 1)th value

n = 9

= 3/4(9 + 1)th value

= 3/4(10)th value

= 7.5th value

This means the value is between the 7th and 8th values

139= 7th value

141 = 8th value

First Quartile = 139 + 141/2

= 280/2

= 140

Therefore, option f)The upper quartile is 140 is correct.

4) The formula for Interquartile range is

Upper quartile - Lower quartile

= 140 - 112

= 28

Therefore, the option h)The interquartile range is 28 is correct.

Looking at the data set below, their is no outlier present.

104, 109, 115, 118, 120, 135, 139, 141, 148

Hence, c)There is an outlier is not correct.

7 0

3 years ago

Read 2 more answers

M∠CBD=4x+52∘

liq [111]

Answer: The value of ∠CBD is 98°.

Step-by-step explanation:

Since we have given that

m∠CBD=4x+52∘

and

m∠ABC=8x−10∘

As we know that they are linear pairs.

As we know that a linear pair is a pair of adjacent angles when two lines get intersected by a line say BC.

So, Sum of linear pair is supplementary.

$\angle CBD+\angle ABC=180^\circ\\\\4x+52+8x-10=180^\circ\\\\12x+42=180^\circ\\\\12x=180^\circ-42^\circ\\\\12x=138^\circ\\\\x=\frac{138}{12}\\\\x=11.5^\circ$

So, m∠CBD = 4x+52=4(11.5)+52=98°

Hence, the value of ∠CBD is 98°.

6 0

3 years ago

Read 2 more answers