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tankabanditka [31]

3 years ago

13

How much water can be contained by a cylindrical tin can with a radius of 15m and a height of 268m if its 5/6 full?

1 answer:

Law Incorporation [45]3 years ago

5 0

First you find the area of the circle using the radius then multiplying that to the height. That gets the full volume. Using that measurement multiply it by 5/6 to figure out what 5/6 of the volume is. Good luck!

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1. Find the values of x.

yawa3891 [41]

Answer:

x = 9√3

Step-by-step explanation:

x^2 = 18^2 - 9^2

x^2 = 324 - 81

x^2 = 243

x = 9√3

7 0

3 years ago

I need to know how to do this one.

Dennis_Churaev [7]

Answer:

$x \approx 11.6906$

I made the assumption those were right triangles.

Step-by-step explanation:

I like your 30 there.

I found the length in orange by doing 55-30=25.

Now we can try to find the length in light purple by doing orange length plus the length you found which is 25+30=55.

So we can use a trig function to find $x$ .

I made another picture to focus our problem more.

Now if you look at the triangle we have here and refer to trig right triangle definitions, we can setup an equation form this.

The opposite side of the angle, whose measurement is $12$ degrees, is $x$ .

The adjacent side of the angle, whose measurement is $12$ degrees, is $55$ .

So I will use the tangent ratio.

$\tan(12^\circ)=\frac{\text{opposite}}{\text{adjacent}}$

$\tan(12^\circ)=\frac{x}{55}$

Multiply both sides by 55:

$55 \cdot \tan(12^\circ)=x$

Now it is handy dandy calculator punching in time:

$11.6906 \approx x$

$x \approx 11.6906$

3 0

3 years ago

YOOOO HELP ME ASAP DUDED BY MIDNIGHT BRO

cupoosta [38]

Answer:

x=5

Step-by-step explanation:

We know that a pentagon is in total 540 degrees. From this, we add all other numbers and set them equal to 540 to solve for x.

So, after adding all the angles and setting them equal to 540, we get this.

21x+435=540

21x=105

x= 5

If you want, plug 5 into x and see if it adds up to 540 to check

21(5)+435=540

7 0

3 years ago

If RT = 6 and RS = 9, then RX =

satela [25.4K]

15 I think I hope this helps and if im wrong I'm soooooo sorry

8 0

4 years ago

Read 2 more answers

The point slope form of the equation of the line that passes through (-5-1) and (10.-7) is

Natalka [10]

Answer:

The standard form of the equation for this line can be:

l: 2x + 5y = -15.

Step-by-step explanation:

Start by finding the slope of this line.

For a line that goes through the two points $(x_0, y_0)$ and $(x_1, y_1)$ ,

$\displaystyle \text{Slope} = \frac{y_{1} - y_{0}}{x_{1} - x_{0}}$ .

For this line,

$\displaystyle \text{Slope} = \frac{(-1) - (-7)}{(-5) - 10} = -\frac{2}{5}$ .

Find the slope-point form of this line's equation using

$\displaystyle \text{Slope} = -\frac{2}{5}$ , and
The point $(-5, -1)$ (using the point $(10, -7)$ should also work.)

The slope-point form of the equation of a line

with slope $m$ and
point $(x_{0}, y_{0})$

should be $l:\; y - y_{0} = m(x - x_0)$ .

For this line,

$\displaystyle m = -\frac{2}{5}$ , and
$x_0 = -5$ , and
$y_0 = -1$ .

The equation in slope-point form will be

$\displaystyle l:\; y - (-1) = -\frac{2}{5}(x - (-5))$ .

The standard form of the equation of a line in a cartesian plane is

$l: \; ax + by = c$

where

$a$ , $b$ , and $c$ are integers. $a \ge 0$ .

Multiply both sides of the slope-point form equation of this line by $5$ :

$l:\; 5 y + 5 = -2x -10$ .

Add $(2x-5)$ to both sides of the equation:

$l: \; 2x + 5y = -15$ .

Therefore, the equation of this line in standard form is $l: \; 2x + 5y = -15$ .

7 0

3 years ago