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N76 [4]
3 years ago
6

If a test has 126 questions and you got 34% how many questions did you get right

Mathematics
2 answers:
Talja [164]3 years ago
7 0
You got 43 problems correct.
Ivenika [448]3 years ago
4 0
43 or 44 it depends on if they rounded or not
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Solve (3)/(?)=(6)/(8)
lbvjy [14]

Answer:

4

Step-by-step explanation:

3/4 = 6/8

5 0
3 years ago
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Bob deposits $2480 into a savings account at 3% interest. At the end of four years how much simple interest does he earn?
vovikov84 [41]
Ok here’s the equation you can run on the next one
A=P(1+rt) A is total P is current amount or starting amount r is annual interest and t is the amount of time
Your answer is
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7 0
3 years ago
Whats this problem i need help
Eva8 [605]

Answer:

perimeter of triangle=sum of all sides

perimeter of triangle = 3/10ft + 3/10ft + 1/10ft

perimeter of triangle =7/10ft

6 0
3 years ago
Rewrite 4 6/7 as an improper fraction.
natima [27]
Im pretty sure its 34/7
4 0
3 years ago
Two semicircles are attached to the sides of a rectangle as shown.
melomori [17]

Answer:

157\ in^{2}

Step-by-step explanation:

we know that

The area of the figure is equal to the area of rectangle plus the area of two semicircles

<u>The area of rectangle is equal to</u>

A=14*5=70\ in^{2}

<u>The area of the small semicircle is equal to</u>

A=\pi r^{2} /2

r=5/2=2.5\ in -----> radius is half the diameter

substitute

A=(3.14)(2.5^{2})/2=9.8125 in^{2}

<u>The area of the larger semicircle is equal to</u>

A=\pi r^{2} /2

r=14/2=7\ in -----> radius is half the diameter

substitute

A=(3.14)(7^{2})/2=76.93\ in^{2}

The area of the figure is equal to

70+9.8125+76.93=156.7425=157\ in^{2}

8 0
3 years ago
Read 2 more answers
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