Question

Evaluate the expression 2x^2-y^1+3x^0 for x=4 and y=7.

Answer 1

Answer:

28

Step-by-step explanation:

We begin with the expression $2x^2-y^1+3x^0$

First, we can simplify this expression before we plug in our values

$2x^2-y^1+3x^0\\\\2x^2-y+3$

Now that it is in its simplest form, we can now evaluate the expression by plugging in x=4 and y=7

$2x^2-y+3\\\\2(4)^2-7+3\\\\2(16)-4\\\\32-4\\\\28$