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tiny-mole [99]
3 years ago
13

Evaluate the expression 2x^2-y^1+3x^0 for x=4 and y=7.

Mathematics
1 answer:
Inga [223]3 years ago
8 0

Answer:

28

Step-by-step explanation:

We begin with the expression 2x^2-y^1+3x^0

First, we can simplify this expression before we plug in our values

2x^2-y^1+3x^0\\\\2x^2-y+3

Now that it is in its simplest form, we can now evaluate the expression by plugging in x=4 and y=7

2x^2-y+3\\\\2(4)^2-7+3\\\\2(16)-4\\\\32-4\\\\28

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