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3 years ago

1. A natural number, when increased by 12, equals 160 times its reciprocal. Find the number.

Mathematics

1 answer:

nlexa [21]3 years ago

3 0

Answer:

Step-by-step explanation:

Let x represent our numbewr

x + 12 = 160/x

x^2 + 12x -160 = 0

(x-20(x+8) = 0

x = -8,20

20 is the only natural number solution.

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Answer:

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4 years ago

How would you solve this equation? Please show steps

Serhud [2]

Simple....

you have: $3x= \sqrt{12-12x}$

So...first you know you're trying to find x..

But, you have a square root on one side...to remove this you'd have to square both sides--->>>

$(3x)^{2} = \sqrt{12-12x} ^{2}$

Leaving you with....

$9x^{2} =12-12x$

Move the terms over and set it equal to zero.

-->>

$9x^{2}+12x-12=0$

Factor out a 3...

$3( 3x^{2} +4x-4=0)$

What multiplies to -12 and adds to 4?

6*-2=-12

6+-2=4

Leaving you with...

$3(3x-2)(x+2)=0$

Remember you're solving for 0....

3x-2=0

3x-2=0
+2 +2

3x=2

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x= $\frac{2}{3}$

Then-->>

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x+2=0
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x=-2

Thus, your answer.

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3 years ago