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3 years ago

What is this half circles radius and how do you find it?

Mathematics

2 answers:

mr Goodwill [35]3 years ago

6 0

Answer:

The radius of the semicircle is 4 cm

Step-by-step explanation:

The diameter of the semicircle is 8 cm

The radius is 1/2 of the diameter

1/2 *8 = 4 cm

The radius of the semicircle is 4 cm

Reptile [31]3 years ago

4 0

$\text{Hey there!}$

$\text{In order for you to find the radius of the circle (in this equation you would)}$ $\text{have to multiply one half from the number 8}$

$\frac{1}{2}\times8=?\\ \frac{1}{2}\times\frac{8}{1} \\ \\1\times8=8\\2\times1=2\\\\8\div2=4$

$\boxed{\boxed{\text{Answer: 04 cm}}}\checkmark$

$\text{Good luck on your assignment and enjoy your day!}$

~ $\frak{LoveYourselfFirst:)}$

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3 years ago

Solve for x if 10/4x-3 = 2

Marysya12 [62]

Answer:

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3 0

3 years ago

Read 2 more answers

PLEASE HELP The Celtics scored a total of 108 points during their last away game. During the game, they scored only 2-point and

Nonamiya [84]

Answer:

2 x 3 + 3 x 12 = 42

Step-by-step explanation:

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6 0

3 years ago

X-20=62 please Help thanks

Flura [38]

Answer:

x = 85

Step-by-step explanation:

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3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Cint%5Climits%5E5_1%20%7B%20%5Cfrac%7BlnR%7D%7B%20R%5E%7B2%7D%20%20%7D%20%5C%2C%20dR%20"

alex41 [277]

Integrate by parts, setting

$\begin{matrix}u=\ln R&&\mathrm dv=\dfrac{\mathrm dR}{R^2}\\\mathrm du=\dfrac{\mathrm dR}R&&v=-\dfrac1R\end{matrix}$

So the integral is

$\displaystyle\int_1^5\frac{\ln R}{R^2}\,\mathrm dR=-\dfrac{\ln R}R\bigg|_{R=1}^{R=5}+\int_1^5\frac{\mathrm dR}{R^2}$
$\displaystyle\int_1^5\frac{\ln R}{R^2}\,\mathrm dR=-\left(\frac{\ln5}5-\frac{\ln1}1)-\frac1R\bigg|_{R=1}^{R=5}$
$\displaystyle\int_1^5\frac{\ln R}{R^2}\,\mathrm dR=-\frac{\ln5}5-\left(\frac15-1\right)$
$\displaystyle\int_1^5\frac{\ln R}{R^2}\,\mathrm dR=\frac15(4-\ln5)$

5 0

4 years ago