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mixas84 [53]
4 years ago
15

What steps do I take to solve y+2>1/2-2 and the solution

Mathematics
1 answer:
kakasveta [241]4 years ago
7 0
<span>y+2>1/2-2 looks a little strange.  Is it OK to combine the last 2 terms?

</span><span>y+2> -3/2

Then y > -2 - 3/2, or y > -7/2.  y must be greater than -7/2, greater than -3.5.</span>
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Answer:5(4a+9)

Step-by-step explanation:

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Factor Completely: 3x2 + 9x - 30
enyata [817]

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3(x-2)(x+5)

Step-by-step explanation:

1. Factor out common term 3

3(x^2 +3x-10)

2. Factor (x^2 +3x-10)

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4 years ago
Please help I'll give brainiest
Komok [63]
For the first is 3864
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A distribution of values is normal with a mean of 220 and a standard deviation of 13. From this distribution, you are drawing sa
Paraphin [41]

Answer:

The interval containing the middle-most 48% of sample means is between 218.59 to 221.41.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributied random variable X, with mean \mu and standard deviation \sigma, the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 220, \sigma = 13, n = 35, s = \frac{13}{\sqrt{35}} = 2.1974

Find the interval containing the middle-most 48% of sample means:

50 - 48/2 = 26th percentile to 50 + 48/2 = 74th percentile. So

74th percentile

value of X when Z has a pvalue of 0.74. So X when Z = 0.643.

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

0.643 = \frac{X - 220}{2.1974}

X - 220 = 0.643*2.1974

X = 221.41

26th percentile

Value of X when Z has a pvalue of 0.26. So X when Z = -0.643

Z = \frac{X - \mu}{s}

-0.643 = \frac{X - 220}{2.1974}

X - 220 = -0.643*2.1974

X = 218.59

The interval containing the middle-most 48% of sample means is between 218.59 to 221.41.

5 0
4 years ago
X(3x + 2) please &lt;3 (expanding brackets)
blagie [28]

Answer:

yes

Step-by-step explanation:

yes

5 0
3 years ago
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