Roots of graphed polynomials! Will mark brainliest if correct!

Negative 1 minus positive two minus positive three minus positive four

mr Goodwill [35]

The answer is -10
hope that helps

7 0

4 years ago

Using the following national income accounting data, compute (a) GDP, (b) NDP, and (c) NI. All figures are in billions. Category

Jet001 [13]

Answer:

(a) GDP = $333.9 billion

(b) NDP = $322.1 billion

(c) NI = $307.7 billion

Step-by-step explanation:

(a) Compute GDP

This can be computed using the following formula:

GDP = Gross Domestic Product = Personal consumption expenditure + net private domestic investment + government purchases + (US exports of goods - US Imports of goods) ......... (1)

Substituting the values into equation (1), we have:

GDP = $219.1 + $52.1 + $59.4 + ($19.8 - $16.5) = $333.9

Since all figures are in billions, we have:

GDP = $333.9 billion

(b) Compute NDP

This can be computed using the following formula:

NDP = Net domestic product = GDP - Consumption of fixed capital ................... (2)

Substituting the values into equation (2), we have:

NDP = $333.90 - $11.8 = $322.1

Since all figures are in billions, we have:

NDP = $322.1 billion

(c) Compute NI

This can be computed using the following formula:

NI = National Income = NDP - Taxes on production and imports - Statistical discrepancy ........... (3)

Substituting the relevant values into equation (3), we have:

NI = $322.1 - $14.4 - $0.0 = $307.7

Since all figures are in billions, we have:

NI = $307.7 billion

8 0

4 years ago

Professor Jennings claims that only 35% of the students at Flora College work while attending school. Dean Renata thinks that th

lisov135 [29]

Answer:

$z=\frac{0.462 -0.35}{\sqrt{\frac{0.35(1-0.35)}{78}}}=2.074$

Now we can calculate the p value with this probability:

$p_v =P(z>2.074)=0.019$

If we use a significance level os 0.05 we see that the p value is lower than the significance level so then we can conclude that the true proportion of students with jobs is higher than 0.35 for this case. If we decrease the significance level to 1% the result changes otherwise not.

Step-by-step explanation:

Information given

n=78 represent the random sample taken

X=36 represent the students with jobs

$\hat p=\frac{36}{78}=0.462$ estimated proportion of students with jobs

$p_o=0.35$ is the value that we want to test

z would represent the statistic

$p_v$ represent the p value

Hypothesis to test

We want to test if the proportion of students with jobs is higher than 0.35, the system of hypothesis are:

Null hypothesis: $p \leq 0.35$

Alternative hypothesis: $p > 0.35$

The statistic is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Replacing the info we got:

$z=\frac{0.462 -0.35}{\sqrt{\frac{0.35(1-0.35)}{78}}}=2.074$

Now we can calculate the p value with this probability:

$p_v =P(z>2.074)=0.019$

If we use a significance level os 0.05 we see that the p value is lower than the significance level so then we can conclude that the true proportion of students with jobs is higher than 0.35 for this case. If we decrease the significance level to 1% the result changes otherwise not.

5 0

4 years ago

Sergei estimated 149% of 67 by performing the following steps. Which statement is true?

enot [183]

Answer: Last option.

Step-by-step explanation:

In order to estimate the percent "n" of a number"x", you need easy numbers to work with, therefore you can round "n" and "x" up or down; but it is important to remember that this estimation does not give you an exact value.

You can observe that Sergei's first step was to round 149% and 67 up, getting this result:

$=105$

To verify if this estimate is less or greater than the actual answer, we can find the actual answer. This is:

$\frac{67*149}{100}=99.83$

Therefore, we can conclude that<em> the estimate is greater than the actual answer because the percent and the number were both rounded up</em>.

4 0

3 years ago

Read 2 more answers

2/x-5=4x<br><br> What is the value of x

kati45 [8]

Answer:

$\large\boxed{x=\dfrac{5\pm3\sqrt3}{2}}$

Step-by-step explanation:

$Domain:\ x-5\neq0\to x\neq5\\\\\dfrac{2}{x-5}=4x\\\\\dfrac{2}{x-5}=\dfrac{4x}{1}\qquad\text{cross multiply}\\\\(4x)(x-5)=(2)(1)\qquad\text{use the distributive property}\\\\(4x)(x)+(4x)(-5)=2\\\\4x^2-20x=2\\\\2^2x^2-20x=2\\\\(2x)^2-2(2x)(5)=2\qquad\text{add}\ 5^2\ \text{to both sides}\\\\(2x)^2-2(2x)(5)+5^2=2+5^2\qquad\text{use}\ (a-b)^2=a^2-2ab+b^2\\\\(2x-5)^2=2+25\\\\(2x-5)^2=27\to2x-5=\pm\sqrt{27}\qquad\text{add 5 to both sides}$

$2x=5\pm\sqrt{9\cdot3}\qquad\text{use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\2x=5\pm\sqrt9\cdot\sqrt3\\\\2x=5\pm3\sqrt3\qquad\text{divide both sides by 2}\\\\x=\dfrac{5\pm3\sqrt3}{2}$

3 0

3 years ago