Huge volume of suspended particles in atmosphere

e. coli are grown on a medium containing lactose. once glucose is added to the medium, the bacteria stop fermenting lactose

djyliett [7]

The lac operon is an operon required for the transport and metabolism of lactose in E.coli. When lactose is introduced to the increased medium, the lac genes are expressed due to the fact allolactose binds to the Lac repressor protein and maintains it from binding to the lac operator. Allolactose is an isomer of lactose. Small quantities of allolactose are shaped when lactose enters into E. coli. allolactose binds to the repressor protein and reasons the conformational change. As a result of this, the repressor can no longer bind to the operator area and falls off. RNA polymerase can then bind to the promoter and transcribe the lac genes. After some time, when the level of lactose decreases as it is metabolized using enzymes, it causes the synthesis of the repressor from the regulator gene. This repressor binds to the operator gene and prevents RNA polymerase from transcribing the operon and the transcription is stopped. This type of law is acknowledged as negative regulation.

Allolactose is a disaccharide comparable to lactose. It consists of the monosaccharides D-galactose and D-glucose linked thru a β1-6 glycosidic linkage alternatively of the β1-4 linkage of lactose. It may additionally occur from the occasional transglycosylation of lactose through β-galactosidase.

Learn more about Allolactose here:

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3 0

2 years ago

Which of these would be considered a cis-regulatory element for a gene? Group of answer choices

ss7ja [257]

Answer:

The correct answer is option d. "A region of DNA sequence upstream of a gene where transcription factors bind".

Explanation:

Cis-regulatory elements (CREs) are fragments of DNA that do not encode to a protein, but regulate the transcription of nearby genes. CREs regulation is based on binding to transcription factors. These elements are vital for the regulation of complex molecular mechanisms that involve the participation of multiple genes. Additionally, CREs could participate in pleiotropy (a single gene being responsible for the development of multiple traits), because a single transcription factor could bind to different CREs.

4 0

3 years ago

Drag the pink labels onto the pink targets to identify the two main phases of the cell cycle. Then drag the blue labels onto the

zavuch27 [327]

Answer:

There is no diagram provided so I will just explain the mitotic cell cycle.

Here’s a quick basic arrangement in chronological order interphase, mitosis, and finally cytokinesis.

So first you start with interphase which consist of three phases G1 phase, S phase, G2 phase. Cellular growth occurs in G1 phase of interphase this is followed by S phase which is simply when DNA replication occurs. Final this is followed by G2 phase or further growth in preparation for mitosis and/or meiosis.

I am only going to explain mitosis but just so I don’t confuse you meiosis can also follow interphase. So mitosis consist of four phases. Prophase, metaphase, anaphase, and telophase.

Prophase: in this phase the nuclear membrane would dissipate and the chromosomes would condense.

Metaphase: then in metaphase the chromosomes would align in the center of the cell and spindle fibers or microtubules would began growth from the centrioles.

Anaphase: by the start of this phase spindle fibers would have attached themselves to the chromosomes kinetochores. In this phase the chromatids would separate and that’s really it as you can tell this is the shortest phase in mitosis.

Telophase: finally the chromosomes would be brought to the polar opposite ends of the cell and the nuclear membrane would reform. Also the chromosomes condensed chromosomes would unravel eventually they would be invisible.

Finally the cell would enter cytokinesis were it would split at the cleavage furrow which would have started in anaphase of telophase, all a cleavage furrow is, is microfilaments “pinching the cell” which is just them pulling on either side of the center of the cell.

3 0

3 years ago

If a stream with a horizontal distance of 5 km begins at an elevation 200 m

Alex

First convert 5 km into m so the units match up

That way you know the stream goes 5,000 m horizontally and 200 m vertically

Then I think you just do rise/run which would be 0.04 m

3 0

3 years ago

Q3. How does the fact that DNA Replicates semiconservatively decrease the

LuckyWell [14K]

If the DNA polymerase did nothing special when a mispairing occurred between an incoming deoxyribonucleoside triphosphate and the DNA template, the wrong nucleotide would often be incorporated into the new DNA chain, producing frequent mutations. The high fidelity of DNA replication, however, depends not only on complementary base-pairing but also on several “proofreading” mechanisms that act sequentially to correct any initial mispairing that might have occurred.

7 0

3 years ago