We have a line y = 1/3x -6
We want a line that is perpendicular to this line
Perpendicular lines have slopes that multiply to -1
1/3 * m = -1
3 * 1/3 *m = -1 * 3
m = -3
The slope of the perpendicular line is -3
y = mx+b where m is the slope and b is the y intercept
y = -3x+b
We have a point on the line ( 7 ,-23)
Substitute this point into the equation
-23 = -3(7)+b
-23 = -21+b
Add 21 to each side
-23+21 = -21+21+b
-2 = b
y = -3x-2
In slope intercept form, the line perpendicular passing through (7,-23) is
y = -3x-2
A. but I would double check on that one first.
You would just have to isolate for x
so it would simply become
-1.56/-7.8
= 0.2
Hey there! :)
Answer:
False.
Step-by-step explanation:
In a point, the coordinates are in the format:
(x, y).
In this instance, x = 5 and y = -3. This means that to plot the point, you would need to:
Move right 5, down 3.
The answer is C that can be the x-intercepts of the parabola
