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Anna007 [38]
3 years ago
5

Can somebody help me

Mathematics
1 answer:
Sergeeva-Olga [200]3 years ago
6 0

cis(x)=\cos x+i\sin x\\\\cis15^o=\cos15^o+i\sin15^o\\\\\cos15^o=\dfrac{\sqrt6+\sqrt2}{4};\ \sin15^o=\dfrac{\sqrt6-\sqrt2}{4}\\\\\text{therefore}\\\\7cis15^o=7\left(\cos15^o+i\sin15^o\right)=7\cos15^o+7i\sin15^o\\\\=7\left(\dfrac{\sqrt6+\sqrt2}{4}\right)+7\left(\dfrac{\sqrt6-\sqrt2}{4}\right)i

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Write a system of two equations in two variables where one equation is quadratic and the other is linear such that the system ha
PilotLPTM [1.2K]

Answer:

This system has no solution:

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Step-by-step explanation:

Hi there!

I propose these two equations:

y = x²

y = 0 · x - 1

This system has no solution because in the quadratic function "y" is always positive for every value of "x", while in the linear function "y" is always -1 for every value of "x". Then, there will not be a pair (x,y) shared by both functions.

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In the attached graphic, you can see that both curves never touch (in red is the quadratic function and in blue is the linear function), hence, the system has no solution.

Have a nice day!

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3 years ago
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Yuki888 [10]
The answer would be 17.
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Answer:

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