Answer:
This system has no solution:
y = x²
y = 0 · x - 1
Step-by-step explanation:
Hi there!
I propose these two equations:
y = x²
y = 0 · x - 1
This system has no solution because in the quadratic function "y" is always positive for every value of "x", while in the linear function "y" is always -1 for every value of "x". Then, there will not be a pair (x,y) shared by both functions.
In other words, there is no value of "x" that satisfies this expression:
x² = 0 · x - 1
In the attached graphic, you can see that both curves never touch (in red is the quadratic function and in blue is the linear function), hence, the system has no solution.
Have a nice day!
I believe the answer should be C.
I am not sure how to do that method... I only know this. (heehee)
The answer would be 17.
This is because, the format for finding out the hypotenuse of a triangle is--
a^2 + b^2 = c^2
So, it would translate to--
15^2 + 8^2 = c^2
225 + 64 = 289
Because 289 = c^2, you need to take the square root of it.
The square root of 289 is 17.
Therefore, your answer is 17.
Answer:
Step-by-step explanation:
Slope = -1.333/2.000 = -0.667
p-intercept = 0/2 = 0.00000
q-intercept = 0/3 = 0.00000