Answer:
Step-by-step explanation:
The formula of a volume of a rectangular box:
<em>l</em><em> - lenght</em>
<em>w</em><em> - width</em>
<em>h</em><em> - height</em>
Therefore the dinemsions of thisp prism are:
Answer:
Linear: The first and third one. (0,5) & (1,1)
Exponential: The second one (above). (-2, 1/16)
Quadratic function: The last one (below). (-3,35)
Step-by-step explanation:
Answer:
<em>Yes, but only if BC ≅ DC; Option B</em>
Step-by-step explanation:
There are 4 possible ways to determine whether two triangles are congruent, and they are the following ;
ASA ( Angle - Side - Angle ),
SAS ( Side - Angle - Side ),
AAS ( Angle - Angle - Side ), and
SSS ( Side - Side - Side )
It is known here that we must prove these triangles congruence through SSS. A triangle can thus be made possible through the congruence of corresponding sides;
Now if we were to create these triangles it would be that BC and DC are, if the triangles were to coincide with one another, the apparent same length if it were that these two Δs really are ≅. Thus;
<em>Solution; Yes, but only if BC ≅ DC</em>
An interesting question! Let's take a look at the rectangular prism first.
[Rectangular Prism]
We know that the formula for the volume of a rectangular prism is:
volume = length * width * height
or more simply
V = L*W*H
All we know is that the volume is 210 cubic meters. We can choose whatever we want for the dimensions to force it to work! We're free to do what we want!
210 = L*W*H
I like 10, that's a nice number. Let's make L = 10.
210 = 10*W*H
Hmm... but now I need W*H to be 21 (think about it, make sure you get why I say that). Well, how about W = 7 and H = 3? That should work.
210 = 10*7*3
It checks! Possible dimensions for the rectangular prism are L = 10 meters, W = 7 meters, and H = 3 meters. There are many other choices of course, but this is a possible choice.
[Triangular Prism]
Same idea, different formula. For a triangular prism, the volume is
V = 1/2 * L*W*H
But the volume is still 210 cubic meters, so we just have
210 = 1/2 * L*W*H
So, one of our dimensions is going to be cut in half. Why don't we just double L to make up for it?
210 = 1/2*(20)*W*H
And we can leave W and H the same
210 = 1/2*20*7*3
Check that it works! A possible choice is L = 20 meters, W = 7 meters and H = 3 meters.
We're done!
We know that
circumference=2*pi*r-------> r=circumference/(2*pi)
circumference=30 in
r=circumference/(2*pi)------> 30/(2*pi)-----> 4.7746 in
the radius of a <span>standard basketball is 4.77 in
</span>
<span>the distance between the ball and the rim is equal to
</span>radius of a basketball rim minus radius of a a standard basketball
radius of a basketball rim =18/2------> 9 in
radius of a a standard basketball=4.77 in<span>
</span>
the distance between the ball and the rim=[9-4.77]------> 4.23 in
the answer is
4.23 in
