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Complete Question
Researchers recorded the speed of ants on trails in their natural environments. The ants studied, Leptogenys processionalis, all have the same body size in their adult phase, which made it easy to measure speeds in units of body lengths per second (bl/s). The researchers found that, when traffic is light and not congested, ant speeds vary roughly Normally, with mean 6.20 bl/s and standard deviation 1.58 bl/s. (a) What is the probability that an ant's speed in light traffic is faster than 5 bl/s? You may find Table B useful. (Enter your answer rounded to four decimal places.)
Answer:
0.7762
Step-by-step explanation:
We solve using z score formula
z = (x-μ)/σ, where
x is the raw score
μ is the population mean
σ is the population standard deviation.
Population mean = 6.20 bl/s
Standard deviation = 1.58 bl/s.
x = 5 bl/s
z = 5 - 6.20/1.58
z = -0.75949
The probability that an ant's speed in light traffic is faster than 5 bl/s is P( x > 5)
Probability value from Z-Table:
P(x<5) = 0.22378
P(x>5) = 1 - P(x<5)
= 1 - 22378
= 0.77622
Approximately to 4 decimal places = 0.7762
The probability that an ant's speed in light traffic is faster than 5 bl/s is 0.7762
They can be 25hours and 10 minutes apart. <span>This is possible because the </span>International dateline is not a straight line<span>.
</span>
Hello!
The line y=1 is horizontal. Therefore, only our y-value will change. As you can see, our y-value is 6 units away from this line. Therefore, we subtract to find the y-value.
1-6=-5
Therefore, our final point is (-2,-5).
I hope this helps!
Answer: 1/2
Step-by-step explanation:
No matter which midsegment you created, it will be one-half the length of the triangle's base (the side you did not use), and the midsegment and base will be parallel lines!
Answer:
15−2(3−2x)=46
Step-by-step explanation:
15−2(3−2x)=46
