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stepladder [879]
3 years ago
15

A fruit company delivers its fruit in two types of boxes: large and small. a delivery of 6 large boxes and 5 small boxes has a t

otal weight of 127 kilograms. a delivery of 2 large boxes and 3 small boxes has a total weight of 51 kilograms. how much does each type of box weigh?
Mathematics
1 answer:
Afina-wow [57]3 years ago
5 0
6 large + 5 small = 127 kg ------------ (1)
2 large + 3 small = 51kg    ------------ (2)

<u>(2) x 3 :</u>
6 large + 9 small = 153 ---------------- (2a)

<u>(2a) - (1) :</u>
4 small = 26
1 small = 6.5kg   ------------ (sub into equation 1)

6 large + 5 small = 127 kg
6 large + 5(6.5) = 127
6 large + 32.5 = 127
6 large = 127 - 32.5
6 large = 94.5
1 large = 15.75 kg

Answer: The small box weighs 6.5kg and the big box weighs 15.75 kg


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I can't figure out how to do this problem. Could somebody help me?
Verizon [17]

start by plugging in the value you already have, in this case, 5 for y.

-4x-3(5)=17

-4x-15=17

-4x=32

x=-8

however, since a is a+1, a would be 7 (making x 8)

also plz tell me if i read this wrong and it’s actually 1,5 rather than a+1 and 5 cause if i did i’m so sorry lol.

8 0
3 years ago
We can use the formula, density = mass over volume, to find the density of a substance. A square metal plate has a density of 10
mash [69]

Answer:

2.15cm^3

Step-by-step explanation:

V = Mass / Density

21.93g / 10.2g/cm^3

2.15cm^3

3 0
3 years ago
Is the data set approximately periodic?
wolverine [178]

Answer:

Option: C is the correct answer.

       C. Periodic with period 4 and amplitude of about 15.

Step-by-step explanation:

We are given the table of values as:

Hour             1 -- 2 -- 3 --  4 --  5 -- 6 -- 7 -- 8 -- 9 -- 10 -- 11

Number       24-41-10-32-26-38-9-31-25-39-12

of boats

As we could see that after every 4 value the values are approximately repeating.

Hence,the data set is approximately periodic.

Also, the amplitude is calculated as:

Average of the maximum and minimum value of each set

We divide the set into 3 sets as follows:

 Hour                       1           2           3            4

Number of boat      24        41          10           32

Here we have amplitude as:

         (41-10)/2=15.5

 Hour                       5           6           7            8

Number of boat      26        38           9           31

  Amplitude is:

          (38-9)/2=14.5

Hour                       9           10          11            12

Number of boat      25        39          12      

            Amplitude is:

            (39-12)/2=13.5

Hence, we see that the amplitude is about 15.

   

4 0
3 years ago
Please look at the included picture, show me your work and please include a good explanation. It would really help me out here.
Jobisdone [24]

These are indeed equivalent, and this identity is one of DeMorgan's laws.

The 6th column is the negation of the 5th column. For example, the first row says

not <em>p</em> or <em>q</em>

is true (T), so the negation would be false (F). The 5th column reads {T, F, T, T}, so the next column should be {F, T, F, F}.

Then in the 7th/last column, you are checking the truth value of the statement

<em>p</em> and not <em>q</em>

For example, in the first row, both <em>p</em> and <em>q</em> are true (T). This means (not <em>q</em>) is false, so (<em>p</em> and not <em>q</em>) is false (F). The last column should end up reading {F, T, F, F}, same as the previous column.

8 0
3 years ago
The residence of a city voted on whether to raise property taxes the ratio of yes to no votes was 2 to 3 is there were 4795 tota
Vinvika [58]

Answer: The number of yes votes = 1918.

Step-by-step explanation:

Given : The ratio of yes to no votes = 2:3

Then the ratio of yes to total votes = \dfrac{2}{2+3}=\dfrac25

Total votes = 4795

Number of yes votes  =  (ratio of yes to total votes) x (Total votes )

= \dfrac{2}{5}\times4795=1918

Hence, the number of yes votes = 1918.

4 0
3 years ago
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