Covert standard form to slope-intercept form
4x + 7y + 3 = 0
7y = -4x - 3
y = (-4/7)x - 3/7 so the slope of this line is -4/7
The slope perpendicular to this is - 1 (-4/7) = 7/4
The required line has equation:-
y - 1 = (7/4)(x - (-2))
y - 1 = (7/4)x + 14/4
y = (7/4)x + 18/4 That is the answer in slope intercept form
Multiply through by 4
4y = 7x + 18
7x - 4y = 18 in Standard form Answer
If you would like to solve 26/57 = 849/5x, you can do this using the following steps:
<span>26/57 = 849/5x /*(5x)
</span>26/57 * (5x) = 849 /*57
26 * 5x = 849 * 57 /26
5x = 48393/26 /5
x = <span>48393/(26*5)
x = 372.25
The correct result would be </span><span>372.25.</span><span>
</span>
Answer: 
.
Step-by-step explanation:
Given problem : 
First we convert mixed fraction into improper fractions as
Now , plug these values in the given expression , we get
![\left(-5\dfrac{5}{6}\right)\div\left(-4\dfrac{9}{10}\right)=-\dfrac{35}{6}\div\left(-\dfrac{49}{10}\right)\\\\=\dfrac{-35}{6}\times\dfrac{-10}{49}\ \ \ [\text{By Property of fraction}]\\\\=\dfrac{350}{294}\\\\=\dfrac{25}{21}=1\dfrac{4}{21}](https://tex.z-dn.net/?f=%5Cleft%28-5%5Cdfrac%7B5%7D%7B6%7D%5Cright%29%5Cdiv%5Cleft%28-4%5Cdfrac%7B9%7D%7B10%7D%5Cright%29%3D-%5Cdfrac%7B35%7D%7B6%7D%5Cdiv%5Cleft%28-%5Cdfrac%7B49%7D%7B10%7D%5Cright%29%5C%5C%5C%5C%3D%5Cdfrac%7B-35%7D%7B6%7D%5Ctimes%5Cdfrac%7B-10%7D%7B49%7D%5C%20%5C%20%5C%20%5B%5Ctext%7BBy%20Property%20of%20fraction%7D%5D%5C%5C%5C%5C%3D%5Cdfrac%7B350%7D%7B294%7D%5C%5C%5C%5C%3D%5Cdfrac%7B25%7D%7B21%7D%3D1%5Cdfrac%7B4%7D%7B21%7D)
Hence, the answer is .
Answer:
Option B. 8 mi, 9 mi, 2 mi
Step-by-step explanation:
The option A doesn't have a set of numbers which could be the lengths of the sides of a triangle. The numbers 1,9,10 mean that the longest side is exactly the sum of the others. The only possible way is they lie in the same line, no triangle is formed
Option C gives the numbers 1,9,11. It's impossible to have a side of 11 when you have the sum of the others less than 11. The maximum extension of the other sides (forming a line) won't be enough to reach the length of 11
Option D is also infeasible for the same reason as the option A. The three lines must be aligned to be connected in its extremes
Option B is the only one who can provide a set of possible lengths of a triangle since the sum of the shortest sides is greater than the third. If we open wide enough the angle between the 2 mi side and the 8 mi side, we would eventually connect the 9 mi side and form a triangle
