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balandron [24]
3 years ago
13

Explain why you cannot use mass or volume alone to identify substances.

Mathematics
1 answer:
melisa1 [442]3 years ago
6 0
That is because mass and volume depend on the size of the sample. The same substance can come in different sizes in which its mass and volume would be different.
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A company manufactures three types of cabinets. It makes 110 cabinets each week. In the first week, the sum of the number of typ
miss Akunina [59]

Answer:

  • In the first week, the number of type-1 cabinets produced was 15,
  • the number of type-2 cabinets produced was 30,
  • the number of type-3 cabinets produced was 65.

Step-by-step explanation:

If we let a, b, c represent the numbers of type-1, type-2, and type-3 cabinets produced in the first week, respectively, we can write three equations in these unknowns:

  • a + b + c = 110 . . . . . total cabinets for the first week
  • a + 2b - c = 10 . . . . relationship of quantities in the first week
  • 3a +0b +c = 110 . . . . total cabinets in the second week

It can be convenient to let a machine solver find the solution to this set of equations. Most graphing calculators can handle it, along with several web sites.

__

Solving by hand, we can subtract the second equation from twice the first. This gives ...

  2(a +b +c) -(a +2b -c) - 2(110) -(10)

  a +3c = 210 . . . . simplify

Subtracting this from 3 times the third equation gives ...

  3(3a +c) -(a +3c) = 3(110) -(210)

  8a = 120 . . . . . simplify

  a = 15 . . . . . . . divide by 8

Using this in the third equation of the original set, we have ...

  3·15 +c = 110

  c = 65 . . . . . . subtract 45

Then, in the first equation, we get ...

  15 + b + 65 = 110

  b = 30 . . . . . . . subtract 80

The solution is (type-1, type-2, type-3) = (15, 30, 65) for the first week.

4 0
4 years ago
Read 2 more answers
A bicycle has a listed price of $577.98 before tax. If the sales tax rate is 6.5%, find the total cost of the bicycle with sales
Salsk061 [2.6K]

Answer:

$615.54

Step-by-step explanation:

Step 1

Write your problem.

577.98 x 6.5% = ?

Step 2

Convert the % to a decimal:

6.5% to 0.065

Step 3

Rewrite the problem with decimal replacing the percentage.

Now the problem looks like this:

577.98 x 0.065 = 37.56

This problem gives the amount of the tax.

Step 4

Add the original price with the tax amount:

577.98 + 37.56 = $615.54 (total cost)

3 0
3 years ago
A survey conducted by the Consumer Reports National Research Center reported, among other things, that women spend an average of
Nookie1986 [14]

Answer:

(a) The probability that a randomly selected woman shop exactly two hours online is 0.217.

(b) The probability that a randomly selected woman shop 4 or more hours online is 0.0338.

(c) The probability that a randomly selected woman shop less than 5 hours online is 0.9922.

Step-by-step explanation:

Let <em>X</em> = time spent per week shopping online.

It is provided that the random variable <em>X</em> follows a Poisson distribution.

The probability function of a Poisson distribution is:

P (X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!} ;\ x=0,1,2,...

The average time spent per week shopping online is, <em>λ </em>= 1.2.

(a)

Compute the probability that a randomly selected woman shop exactly two hours online over a one-week period as follows:

P (X=2)=\frac{e^{1.2}(1.2)^{2}}{2!} =0.21686\approx0.217

Thus, the probability that a randomly selected woman shop exactly two hours online is 0.217.

(b)

Compute the probability that a randomly selected woman shop 4 or more hours online over a one-week period as follows:

P (X ≥ 4) = 1 - P (X < 4)

              = 1 - P (X = 0) - P (X = 1) - P (X = 2) - P (X = 3)

              =1-\frac{e^{1.2}(1.2)^{0}}{0!}-\frac{e^{1.2}(1.2)^{1}}{1!}-\frac{e^{1.2}(1.2)^{2}}{2!}-\frac{e^{1.2}(1.2)^{2}}{3!}\\=1-0.3012-0.3614-0.2169-0.0867\\=0.0338

Thus, the probability that a randomly selected woman shop 4 or more hours online is 0.0338.

(c)

Compute the probability that a randomly selected woman shop less than 5 hours online over a one-week period as follows:

P (X < 5) = P (X = 0) + P (X = 1) + P (X = 2) + P (X = 3) + P (X = 4)

              =\frac{e^{1.2}(1.2)^{0}}{0!}+\frac{e^{1.2}(1.2)^{1}}{1!}+\frac{e^{1.2}(1.2)^{2}}{2!}+\frac{e^{1.2}(1.2)^{3}}{3!}+\frac{e^{1.2}(1.2)^{4}}{4!}\\=0.3012+0.3614+0.2169+0.0867+0.0260\\=0.9922

Thus, the probability that a randomly selected woman shop less than 5 hours online is 0.9922.

8 0
4 years ago
Which function has a horizontal asymptote of y = 3?
adoni [48]

Answer:

f(x) = 2(4^x)+3

this gets you horizontal asymptote of y = 3

Step-by-step explanation:

6 0
2 years ago
Which expression is equivalent to (x3 · x2)5? x10
marysya [2.9K]
<h2> The given expression is equivalent to x^{5}.</h2>

Step-by-step explanation:

The given expression is

x^3.x^2

To write the given expression is equivalent = ?

The given expression is

x^3.x^2

We know that,

The exponential identity,

a^{m}.a^{n}=a^{m+n}

= x^{3+2}

= x^{5}

∴ The given expression is equivalent = x^{5}

Thus, the given expression is equivalent to x^{5}.

You can also see:

brainly.com/question/4456975

8 0
4 years ago
Read 2 more answers
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